myhelper: S.chand Class 8 Maths Solution Chapter 6 Factorisation of Algebraic Expressions Exercise 6 F

Exercise 6 F

Factorise :

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Question 1

$a^{2}+5 a+6$

Sol :

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Question 2

$x^{2}+7 x+12$

Sol :

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Question 3

$m^{2}+13 m+42$

Sol :

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Question 4

$a^{2}+25 a-54$

Sol :

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Question 5

$t^{2}+9 t-36$

Sol :

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Question 6

$a^{2}+5 a-50$

Sol :

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Question 7

$x^{2}-4 x-5$

Sol :

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Question 8

$y^{2}-10 y+16$

Sol :

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Question 9

$x^{2}-2 x-24$

Sol :

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Question 10

$y^{2}+2 y-48$

Sol :

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Question 11

$n^{2}-3 n-40$

Sol :

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Question 12

$y^{2}-11 y+24$

Sol :

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Question 13

$48+22 x-x^{2}$

Sol :

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Question 14

$x^{2}-29 x+204$

Sol :

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Question 15

$p^{2}-5 p-176$

Sol :

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Question 16

$n^{2}-19 n-92$

Sol :

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Question 17

$j^{2}-11 j-102$

Sol :

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Question 18

$2 a^{3}+10 a^{2}-28 a$ [Hint. First take out the common factor $2 a$ .]

Sol :

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Question 19

$12 b+15-3 b^{2}$

Sol :

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Question 20

$3 c^{5}-18 c^{4}-48 c^{3}$

Sol :

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Question 21

$b^{2} c^{3}+8 b c^{4}+12 c^{5}$

Sol :

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Question 22

$a^{4}-5 a^{2}-36$

Sol :

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Question 23

$y^{4}+4 y^{2}-32$

Sol :

Multiple Choice Questions (MCQs)

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Question 24

Which is the correct factorisation of $x^{2}-10 x-24$ ?

(a) $(x-2)(x+12)$

(b) $(x+4)(x-6)$

(c) $(x-4)(x-6)$

(d) $(x+2)(x-12)$

Sol :

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Question 25

One of the factors of $(x-y)^{2}-4(x-y)-45$ is

(a) $(x-y+9)$

(b) $(x-y-5)$

(c) (x-y-9)

(d) (x+y+5)

High Order Thinking Skills (HOTS)

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Question 26

Which value of $b$ would make $y^{2}+b y-24$ factorable ?

(a) 14

(b) 11

(c) 5

(d) 25

Sol :

S.chand Class 8 Maths Solution Chapter 6 Factorisation of Algebraic Expressions Exercise 6 F

Exercise 6 F

Question 1

Question 2

Question 3

Question 4

Question 5

Question 6

Question 7

Question 8

Question 9

Question 10

Question 11

Question 12

Question 13

Question 14

Question 15

Question 16

Question 17

Question 18

Question 19

Question 20

Question 21

Question 22

Question 23

Question 24

Question 25

Question 26

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