Exercise 5 E
Divide :
Q1 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 1
a2+6a+5 by a+1
Sol :
Q2 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 2
x2−3x+2 by x−1
Sol :
Q3 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 3
x2+4x−21 by x+7
Sol :
Q4 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 4
14−17x+5x2 by 2−x
Sol :
Q5 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 5
14x2+13x−15 by 7x−4
Sol :
Q6 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 6
x3+3−4x+2x2 by x−2
Sol :
Q7 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 7
x4+4x−2x2+x3−10 by x−2
Sol :
Q8 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 8
8x2+21x+x3+18 by 6+5x+x2
Sol :
Using division find whether or not the first polynomial is a factor of the second:
Q9 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 9
x−7;x2−3x−28
Sol :
Q10 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 10
2x−3;6x3+x2−19x+6
Sol :
Q11 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 11
x−6;x2−12x+40
Sol :
Q12 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 12
6p3+5p2+4 by (2p+1)
Sol :
Q13 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 13
x3+4x−3 by (x+5)
Sol :
Q14 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 14
What should be added to 6x5+4x4−27x3−7x2−27x−6 so that the resulting polynomial is exactly divisible by (2x2−3).
Sol :
Multiple Choice Questions (MCQs)
Q15 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 15
What will be the remainder when 6x5+4x4−27x3 −7x2+27x+32 is divided by (2x2−3)?
(a) 12
(b) −12
(c) 0
(d) −92
Sol :
Q16 | Ex-5E | Class 8 | SChand Composite Maths | Algebraic Expressions and Special Products | myhelper
Question 16
What should be subtracted from 8x4+14x3 −2x2+7x−8 so that the resulting polynomial is exactly divisible by 4x2+3x−2.
(a) −14x+10
(b) 13x−9
(c) 14x−10
(d) −10
Sol :
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