S.chand publication New Learning Composite mathematics solution of class 8 Chapter 6 Factorisation of Algebraic Expressions Exercise 6F

 Exercise 6F


Q1 | Ex-6F | Class 8 | SChand | New Learning Composite maths | Factorisation of Algebraic Expressions | myhelper

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 Question 1

Factorise the following:

y2 + 4y + 3

Sol :
=y2+3y+y+3

=y(y+3)+1(y+3)

=(y+1)(y+3)



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 Question 2

a2 + 12a + 27

Sol :

=a2+9a+3a+27
=a(a+9)+3(a+9)
=(a+3)(a+9)



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 Question 3

(3) x2 + 12x + 32

Sol :
=x2+8x+4x+32
=x(x+8)+4(x+8)

=(x+8)(x+4)



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 Question 4

p2 – 11p + 24

Sol :
=p2 – 11p + 24

=p(x-8)-3(x-8)


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 Question 5

x2 – 15x + 44

Sol :

=x2–15x+44
=x(x-11)-4(x-11)

=(x-11)(x-4)


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 Question 6

m2 – 15m + 56

Sol :
=m2 – 15m + 56
=m(m-8)-7(m-8)

=(m-8)(m-7)



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 Question 7

x2 + x – 30

Sol :
=x2+x–30
=x(x+6)-5(x+6)
=(x+6)(x-5)


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 Question 8

a2 – 3a – 18

Sol :

=a2–6a+3a–18

=a(a-6)+3(a-6)

=(a-6)(a+3)


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 Question 9

b2b – 56

Sol :

=b2 –b – 56

=b(b-8)+7(b-8)

=(b-8)(b+7)



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 Question 10

t2 – 20t – 125

Sol :

=t2–20t–125

=t(t-25)+5(t-25)

=(t-25)(t+5)


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 Question 11

u2 – 7u – 30

Sol :

=u2 – 7u – 30

=u(u-10)+3(u-30)



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 Question 12

x2 – 43x + 42

Sol :

=x2–42x-x+42
=x(x-42)-1(x-12)

=(x-42)(x-1)



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 Question 13

k2 + 12k – 160

Sol :

=k2+20k-8k-160

=k(k+20)-8(k+20)


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 Question 14

x2 + 5x – 24

Sol :

=x2 + 5x – 24

=x(x+8)-3(x+8)

=(x+8)(x-3)


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 Question 15

c2– 19c + 78

Sol :

=c2–13c-9c+78
=c(c-13)+9(c-13)
=(c-13)(c+9)



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 Question 16

y+ 2y – 48

Sol :

=y2+8y-6y–48

=y(y+8)-6(y+8)

=(y+8)(y-6)


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 Question 17

a2 + 9a – 36

Sol :

=a2+12a-3a-36

=a(a+12)-3(a+12)

=(a+12)(a-3)



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 Question 18

m2 – 3m – 40

Sol :

=m2–5m+2m–10

=m(m-5)+2(m-5)

=(m-5)(m+2)



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 Question 19

t2 – 17t – 84

Sol :

=t2–21t+4t-84

=t(t-21)+4(t-21)

=(t-21)(t+4)



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 Question 20

x2 – 13x – 68

Sol :

=x2– 13x – 68

=x(x-17)-4(x-17)
=(x-17)(x-4)



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 Question 21

u2 + 6u – 112

Sol :
=
u2 + 6u – 112

=u(u+4)-8(u+14)

=(u+14)(u-8)

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