Exercise 8B
Q1 | Ex-8B | Class 8 | S.Chand | Composite maths | Profit,Loss and Discount |Ch-8 | myhelper
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QUESTION 1
The marked price of a saree is ₹ 3800 . The shopkeeper offers a discount of 15% during sale time . What is the selling price of saree ?
Sol :
Given : M.P = 3800 and Discount = 15%
$\text{S.P}=\dfrac{100-Discount\%}{100}\times \text{M.P}$
$=\dfrac{100-15}{100}\times 3800$
$=\dfrac{85}{100}\times 3800$
= 3,230
Q2 | Ex-8B | Class 8 | S.Chand | Composite maths | Profit,Loss and Discount |Ch-8 | myhelper
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QUESTION 2
The marked price of a shirt is ₹ 270 and it is available at ₹ 237.60 after discount . What is the rate of discount ?
Sol :
At , first we have to find discount
Discount = 270 - 237.60
= 32.4
We know that $\text{Discount}\%=\dfrac{\text{discount}}{\text{M.P}}\times 100$
$=\dfrac{32.4}{270}\times 100$
= 12 %
Q3 | Ex-8B | Class 8 | S.Chand | Composite maths | Profit,Loss and Discount |Ch-8 | myhelper
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QUESTION 3
A person purchased a shirt for ₹ 600 , after a discount of 20% was offered on the market price of the shirt ?
Sol :
Given : Discount % = 20 %
let's find M.P of shirt
$\text{M.P}=\dfrac{\text{S.P}}{100-Discount\%}\times 100$
$=\dfrac{600}{100-20}\times 100$
$=\dfrac{600}{80}\times 100$
= 750
Q4 | Ex-8B | Class 8 | S.Chand | Composite maths | Profit,Loss and Discount |Ch-8 | myhelper
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QUESTION 4
A shopkeeper earns a profit of 10% after allowing a discount of 20% on the market price . Find the cost price of the article whose marked price is ₹ 880.
Sol :
Given : Discount % = 20 % , Profit = 10 % , M.P = 880
$\text{S.P}=\dfrac{100-\text{Discount}\%}{100}\times \text{M.P}$
$=\dfrac{100-20}{100}\times 880$
$=\dfrac{80}{100}\times 880$
S.P = 704
We know Profit = S.P - C.P and $\text{Profit}\%=\dfrac{\text{Profit}}{\text{C.P}}\times 100$ or $\text{Profit}\%=\dfrac{\text{S.P - C.P}}{\text{C.P}}\times 100$
$\text{Profit}\%=\left(\dfrac{\text{S.P}}{\text{C.P}} - \dfrac{\text{C.P}}{\text{C.P}} \right)\times 100$
$\text{Profit}\%=\left(\dfrac{\text{S.P}}{\text{C.P}} - 1 \right)\times 100$
$10=\left(\dfrac{704}{\text{C.P}} - 1 \right)\times 100$
$\dfrac{10}{100}=\dfrac{704}{\text{C.P}} - 1 $
$\dfrac{1}{10}+1=\dfrac{704}{\text{C.P}} $
$\dfrac{1+10}{10}=\dfrac{704}{\text{C.P}} $
$\dfrac{11}{10}=\dfrac{704}{\text{C.P}} $
$\text{C.P}=\dfrac{704\times 10}{11}$
C.P = 640
Q5 | Ex-8B | Class 8 | S.Chand | Composite maths | Profit,Loss and Discount |Ch-8 | myhelper
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QUESTION 5
A shopkeeper marks his goods 20% above the cost price , but allows 30% discount for cash . What is his net loss percent ?
Sol :
According to question , M.P =C.P + (20% of C.P)
$\text{M.P}=\text{C.P} + \dfrac{20}{100}\times \text{C.P}$
$\text{M.P}=\text{C.P} + \dfrac{\text{C.P}}{5}$
$\text{M.P}=\dfrac{6}{5}\times \text{C.P}$
Also ,
$\text{S.P}=\dfrac{100-\text{Discount}\%}{100}\times \text{M.P}$
$\text{S.P}=\dfrac{100-30}{100}\times \dfrac{6}{5}\times \text{C.P}$
$\text{S.P}=\dfrac{70}{100}\times \dfrac{6}{5}\times \text{C.P}$
$\text{S.P}=\dfrac{7}{5}\times \dfrac{3}{5}\times \text{C.P}$
$\text{S.P}=\dfrac{21}{25}\times \text{C.P}$
And putting values of S.P in below formula , we get
$\text{C.P}=\left(\dfrac{100}{100-\text{loss}\%}\right)\times \text{S.P}$
$\text{C.P}=\left(\dfrac{100}{100-\text{loss}\%}\right)\times \dfrac{21}{25}\times \text{C.P}$
$\text{C.P}\times \dfrac{25}{21}\times \dfrac{1}{\text{C.P}}=\dfrac{100}{100-\text{loss}\%}$
$\dfrac{25}{21}=\dfrac{100}{100-\text{loss}\%}$
$2100=25(100-\text{loss }\%)$
$\dfrac{2100}{25}=(100-\text{loss }\%)$
$84=100-\text{loss }\%$
$\text{loss }\%=100-84$
Loss % = 16 %
Q6 | Ex-8B | Class 8 | S.Chand | Composite maths | Profit,Loss and Discount |Ch-8 | myhelper
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QUESTION 6
The marked price of a T-shirt is ₹ 200 . After allowing a discount of 20% on the marked price , the shopkeeper makes a profit of ₹ 16 . Find the gain percent ?
Sol :
Lets find Selling Price of t-shirt
$\text{S.P}=\dfrac{100-\text{Discount}\%}{100}\times \text{M.P}$
$=\dfrac{100-20}{100}\times 200$
$=\dfrac{80}{100}\times 200$
S.P = 160
Profit = SP - CP
16=160-CP
C.P = 160-16
C.P = 144
$\text{Gain}\%=\dfrac{\text{gain}}{C.P}\times 100$
$\text{Gain}\%=\dfrac{16}{144}\times 100$
$=11\dfrac{1}{9}\%$
Q7 | Ex-8B | Class 8 | S.Chand | Composite maths | Profit,Loss and Discount |Ch-8 | myhelper
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QUESTION 7
A shopkeeper allows a discount of 10% to his customers and still gains 20% . Find the marked price of the article which cost ₹ 450 .
Sol :
We know that
$\text{C.P}=\left(\dfrac{100}{100+\text{Gain\%}}\right)\times \text{S.P}$
$450=\left(\dfrac{100}{100+20}\right)\times \text{S.P}$
$450=\dfrac{100}{120}\times \text{S.P}$
$\text{S.P}=\dfrac{450\times 120}{100}$
S.P = 540
Putting value of S.P in below formula
$\text{M.P}=\dfrac{\text{S.P}}{100-\text{Discount}\%}\times 100$
$\text{M.P}=\dfrac{540}{100-10}\times 100$
$=\dfrac{540}{90}\times 100$
M.P = 600
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