S.chand Composite Maths books class 8 maths solution chapter 28 Data Handling exercise 28 B

 EXERCISE 28 B


Q1 | Ex-28B | Class 8 | SChand Composite Maths | Data Handling | myhelper

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Question 1

Fill in the blanks:
(i) The difference between the maximum and the minimum observations in a data is called the ___ of the data.

Sol : Range


(ii) The number of observations in a particular class interval is called the ___ of the class interval.

Sol : Frequency



Q2 | Ex-28B | Class 8 | SChand Composite Maths | Data Handling | myhelper

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Question 2

Find:
(i) Lower limit of the class interval 46 - 53

Sol : 46

(ii) Upper limit of the class interval 30 — 35

Sol : 35

(iii) The range of the data 2 , 9 , 17 , 25 , 4 , 11

Sol : 23



Q3 | Ex-28B | Class 8 | SChand Composite Maths | Data Handling | myhelper

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Question 3

Find the class marks of the following table:

Weights in kg 10-20 20-30 30-40 40-50 50-60
Class-marks -- -- -- -- --

Sol :

Weights in kg 10-20 20-30 30-40 40-50 50-60
Class-marks $=\dfrac{10+20}{2}=15$ $=\dfrac{20+30}{2}=25$ $=\dfrac{30+40}{2}=35$ $=\dfrac{40+50}{2}=45$ $=\dfrac{50+60}{2}=55$



Q4 | Ex-28B | Class 8 | SChand Composite Maths | Data Handling | myhelper

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Question 4

The following are the monthly rents (in rupees) of 30 shops
42,49,37,82,37,75,62,54,79,84,75,63,44,74,36,69,54,48,74,39,48,45,61,71,47,38,80,51,31,47.

Using the class intervals of equal width in which one class interval being 40-50 (excluding 50) . Construct a frequency table for the above data .

Sol :

Monthly rent (in rupees) 30-40 40-50 50-60 60-70 70-80 80-90
f 6 8 3 4 6 3



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Question 5

On the first day of school , a school bus brought 40 students to a high school . Their wages were as follows:
13,11,9,10,15,6,5,8,15,16,17,7,8,10,13,17,14,12,14,13,6,11,9,10,12,17,16,7,8,9,6,10,6,8,13,9,6,8,12
Group the ages into four equal classes with class intervals 4-8 etc and construct a frequency table

Sol :

Age 4-8 8-12 12-16 16-20
f 8 15 12 5



Q6 | Ex-28B | Class 8 | SChand Composite Maths | Data Handling | myhelper

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Question 6

Find the mean of each of the following frequency distributions.

Class 0-10 10-20 20-30 30-40 40-50 50-60 60-70
Frequency 4 4 7 10 12 8 5

Sol : 
Class IntervalFrequency(f)Class Marks(x)f.x
0-104$\dfrac{0+10}{2}=5$4×5=20
10-204$\dfrac{10+20}{2}=15$4×15=60
20-307$\dfrac{20+30}{2}=25$7×25=175
30-4010$\dfrac{30+40}{2}=35$10×35=350
40-5012$\dfrac{40+50}{2}=45$12×45=540
50-608$\dfrac{50+60}{2}=55$8×55=440
60-705$\dfrac{60+70}{2}=65$5×65=325
𝝨=50
𝝨fx=1910


$\overline{x}=\dfrac{\sum fx}{\sum f}=\frac{1910}{50}$
=38.2





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