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S.chand books class 8 maths solution chapter 14 Factorisation Exercise 14 H

EXERCISE 14 H


Factorise:


Q1 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 1

2x2 + 7x + 5

Sol :

210551

=2x2+2x+5x+5

=2x(x+1)+5(x+1)

=(2 x+5)(x+1)



Q2 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 2

4x2 + 15x + 14

Sol :

=14×4=56

256228214771


=4x2+8x+7x+14

=4x(x+2)+7(x+2)

=(4x+7)(x+2)



Q3 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 3

4x2+ 28x + 13

Sol :

=13×4=52

25222613131


=4x2+28x+13

=2x(2 x+1)+13(2x+1)

=(2x+13)(2x+1)



Q4 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 4

3x2 + 13x + 14

Sol :

=3x2+x+12x+4

=x(3 x+1)+4(3 x+1)

=(x+4)(3x+1)



Q5 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 5

4x2 + 8x - 5

Sol :

=4x22x+10x5

=2x(2x-1)+5(2x-1)

=(2x+5)(2x-1)



Q6 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 6

2x2 - 5x -12

Sol :

=2x28x+3x12

=2 x(x-4)+3(x-4)

=(2 x+3)(x-4)



Q7 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 7

13a2 + 37a - 6

Sol :

=13×6=78

27833913131



=13a2+39a2a6

=13 a(a+3)-2(a+3)

=(13 a-2)(a+3)



Q8 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 8

40a2 + a -6

Sol :

=40a215a+16a6

=5a(8 a-3)+2(8 a-3)

=(5 a+2)(8 a-3)



Q9 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 9

4a2 - 16a + 15

Sol :

=4a26x10x+15

=2a(2a-3)-5(2a+3)

=(2a-5)(2a-3)




Q10 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 10

6 - 9y - 27y2

Sol :

⇒-27y2-9y+6 

⇒-3(9y2+3y-2)

LCM of (9×2=18) is 

2 18
3 9
3 3

1

⇒-3(9y2+6y-3y-2)

⇒-3[3y(3y+2)-1(3y+2)]

⇒-3(3y-1)(3y+2)

⇒3(1-3y)(3y+2)



Q11 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 11

1 - t - 6t2

Sol :

⇒-6t2-t+1

⇒-1(6t2+t-1)

26
33

1
⇒-1(6t2+3t-2t-1)
⇒-1[3t(2t+1)-1(2t+1)]
⇒-1(3t-1)(2t+1)
⇒(1-3t)(2t+1)


Q12 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 12

2a2 + 7ab - 15b2

Sol :

=2a2+10ab3ab15b2

=2a(a+5b)-3b(a+5b)

=(2a-3b)(a+5b)



Q13 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 13

2x2 + 12x + 10

Sol :

=2(x2+6x+5)

=2(x2+6x+5)

=2(x2+x+5x+5)

=2x(x+1)+5(x+1)

=2(x+5)(x+1)



Q14 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 14

6a2 + a - 2

Sol :

=6×2=12

212
26
33

1

=6a2+4a3a2

=2a(3a+2)-1(3a+2)

=(2a-1)(3a+2)



Q15 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 15

6a3 + 3a2 - 3a

Sol :

3a(2a2+a1)

3a(2a2+2aa1)

3a[2a(a+1)-1(a+1)]

3a(2a-1)(a+1)



Q16 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 16

3x5 - 11x3 - 4x

Sol :

x(3x411x24)=0

x[3x411x24=0

x[3x412x2+x34]

x[3x2(x24)+1(x24)]

x[(3x2+1)(x24)]

(x)[(x+2)(x2)](3x2+1)



Q17 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 17

6a6 - 21a4 - 12a2

Sol :

a2(6a421a212)

3a2(2a47a24)

3a2(2a48a2+a24)

3a2[2a2(a24)+1(a24)]

3a2[(2a2+1)(a24)]

3a2(2a2+1)(a2)(a+2)



Q18 | Ex-14H | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 18

-12m5 - m3 + m

Sol :

m[12m4+m21]

m[12m4+4m23m21]

m[4m2(3m2+1)1(3m2+1)]

m[(4m21)(3m2+1)]

m[(2m)2(1)2](3m2+1)

(m)(3m2+1)[(2m+1)(2m1)]

m(3m2+1)(2m+1)(12m)

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