S.chand books class 8 maths solution chapter 14 Factorisation exercise 14 B

Exercise 14 B


Factorise:

Q1 | Ex-14B | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 1

(x+3)x + (x+3)y

Sol :

Taking common (x+3)

=(x+3)(x+y)



Q2 | Ex-14B | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 2

(a+1)x + (a+1)y

Sol :

Taking common (a+1)

=(a+1)(x+y)



Q3 | Ex-14B | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 3

a(m+n) + b(m+n)

Sol :

Taking common (m+n)

=(m+n)(a+b)



Q4 | Ex-14B | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 4

2(x-a)2 + (x-a)

Sol :

=2(x-a)(x-a) + (x-a)

Taking common (x-a)

=(x-a)[2(x-a)+1]

=




Q4 | Ex-14B | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 4

a(a+b) - b(b+a)

Sol :




Q6 | Ex-14B | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 6

(p+q)2 + 3(p+q)

Sol :




Q7 | Ex-14B | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 7

(x+y)2 + (x+y)
Sol :



Q8 | Ex-14B | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 8

21(4p-5q)3 + 14(4p-5q)2
Sol :

=21(4p-5q)(4p-5q)2 + 14(4p-5q)2

Taking common

=(4p-5q)[21(4p-5q)+14]

=(4p-5q)[84p-105q+14]

=(4p-5q)[7(12p-15q+2)]

=7(4p-5q)(12p-15q+2)



Q9 | Ex-14B | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 9

a(x-y) - b(x-y)2

Sol :




Q10 | Ex-14B | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 10

a(x+y+z) + b(x+y+z) + c(x+y+z)

Sol :




Q11 | Ex-14B | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 11

(a+b)3 - 3ab(a+b)
Sol :




Q12 | Ex-14B | Class 8 | S.Chand | Composite maths | chapter 14 |Factorisation | myhelper

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Question 12

a(a-2c) + b(a-2c) + (2c-a)

Sol :















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