Exercise 24A
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Q1 | Ex-24A | Class 8 | RS AGGARWAL | chapter 24 | Pie Charts
Question 1:
The monthly income of family is ₹ 28800. The monthly expenditure of the family on various items is given below.
| Item | Rent | Food | Clothing | Education | Saving |
| Expenditure (in ₹) | 8000 | 10800 | 5600 | 3600 | 800 |
Answer 1:
Monthly income of the family = ₹28,800
Central angle for each item=(Expenditure per month on various itemsMonthly income×360)°
Calculation of central angles
| Items | Expenditure(in ₹) | Central angle |
| Rent | 8000 | 100º |
| Food | 10800 | 135º |
| Clothing | 5600 | 70º |
| Education | 3600 | 45º |
| Savings | 800 | 10º |
Construction of pie chart
Steps of construction
1. Draw a circle of any convenient radius.
2. Draw a horizontal radius of this circle.
3. Draw sectors whose central angles are 100º, 135º, 70º, 45º and 10º.
4. Shade the sectors so obtained differently and label each one of them.
Thus, the pie chart is obtained as follows.
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Q2 | Ex-24A | Class 8 | RS AGGARWAL | chapter 24 | Pie Charts
Question 2:
There are 900 creatures in a zoo as per list given below:
| Beast animals | Other land animals | Birds | Water animals | Reptiles |
| 150 | 400 | 175 | 125 | 50 |
Represent the above data by a pie chart.
Answer 2:
Total number of creatures=900Central angle of each component=(number of creatures in each type total number of creatures×360)°Calculation of central angles
| Creatures | Number of creatures | Central angle |
|---|---|---|
| Beast animals | 150 | 60° |
| Other land animals | 400 | 160° |
| Birds | 175 | 70° |
| Water animals | 125 | 50° |
| Reptiles | 50 | 20° |
Construction of pie chart Steps of construction:1. Draw a circle of any convenient radius.2. Draw a horizontal radius of this circle.3. Draw sectors whose central angles are 60°, 160°, 70°, 50° and 20°.4. Shade the sectors so obtained differently and label each one of them.Thus, we obtain the required pie chart as shown in the figure below.
Q3 | Ex-24A | Class 8 | RS AGGARWAL | chapter 24 | Pie Charts
Question 3:
Various modes of transport used by 1260 students in a given school are given below:
| School bus | Private bus | Bicycle | Rickshaw | On foot |
| 350 | 245 | 210 | 175 | 280 |
Represent the above data by a pie chart.
Answer 3:
Total number of students=1260Central angle of each component=(number of students using that modetotal number of students×360)°Calculation of central angles
| Mode of transport | Number of students | Central angle |
|---|---|---|
| School bus | 350 | 100° |
| Private bus | 245 | 70° |
| Bicycle | 210 | 60° |
| Rickshaw | 175 | 50° |
| On foot | 280 | 80° |
Construction of pie chartSteps of construction:1. Draw a circle of any convenient radius.2. Draw a horizontal radius of this circle.3. Draw sectors whose central angles are 100°, 70°, 60°, 50° and 80°.4. Shade the sectors so obtained differently and label each one of them.Thus, we obtain the required pie chart as shown in the figure below.
Q4 | Ex-24A | Class 8 | RS AGGARWAL | chapter 24 | Pie Charts
Question 4:
The data given below shows number of hours spent by a school boy on different activities on a working day.
| Activity | School | Homework | Play | Sleep | Others | Total |
| Number of hours | 7 | 4 | 2 | 8 | 3 | 24 |
Represent the above data by a pie chart.
Answer 4:
Total number of hours=24Central angle of each component=(number of hours spent on each activitytotal number of hours×360)°Calculation of central angles
| Activity | Number of hours | Central angle |
|---|---|---|
| School | 7 | 105° |
| Home work | 4 | 60° |
| Play | 2 | 30° |
| Sleep | 8 | 120° |
| Others | 3 | 45° |
Construction of pie chartSteps of construction:1. Draw a circle of any convenient radius.2. Draw a horizontal radius of this circle.3. Draw sectors whose central angles are 105°, 60°, 30°, 120° and 45°.4. Shade the sectors so obtained differently and label each one of them.Thus, we obtain the required pie chart as shown in the figure below.
Q5 | Ex-24A | Class 8 | RS AGGARWAL | chapter 24 | Pie Charts
Question 5:
The data on religion wise division of 1080 workers of a factory are given below:
| Religion | Hindu | Muslim | Sikh | Christian |
| Number of workers | 450 | 270 | 255 | 105 |
Draw a pie chart to represent the above data.
Answer 5:
Total number of workers=1080Central angle of each religion=(number of workers in each religiontotal number of workers×360)°Calculation of central angles
| Religion | Marks obtained | Central angle |
|---|---|---|
| Hindu | 450 | 150° |
| Muslim | 270 | 90° |
| Sikh | 255 | 85° |
| Christian | 105 | 35° |
Construction of pie chartSteps of construction:1. Draw a circle of any convenient radius.2. Draw a horizontal radius of this circle.3. Draw sectors whose central angles are 150°, 90°, 85° and 35°.4. Shade the sectors so obtained differently and label each one of them.Thus, we obtain the required pie chart as shown in the figure below.
Q6 | Ex-24A | Class 8 | RS AGGARWAL | chapter 24 | Pie Charts
Question 6:
The marks obtained by Sudhir in an examination are given below:
| Subject | English | Hindi | Mathematics | Science | Social science |
| Marks obtained | 105 | 75 | 150 | 120 | 90 |
Represent the above data by a pie chart.
Answer 6:
Total marks obtained=(105+75+150+120+90)=540Central angle of each subject=(marks obtained in each subjecttotal marks obtained×360)°Calculation of central angles
| Subject | Marks obtained | Central angle |
|---|---|---|
| English | 105 | 70° |
| Hindi | 75 | 50° |
| Mathematics | 150 | 100° |
| Science | 120 | 80° |
| Social science | 90 | 60° |
Construction of pie chartSteps of construction:1. Draw a circle of any convenient radius.2. Draw a horizontal radius of this circle.3. Draw sectors whose central angles are 70°, 50°, 100°, 80° and 60°.4. Shade the sectors so obtained differently and label each one of them.Thus, we obtain the required pie chart as shown in the figure below.
Q7 | Ex-24A | Class 8 | RS AGGARWAL | chapter 24 | Pie Charts
Question 7:
The following table gives the number of different fruits kept in a hamper.
| Type of fruit | Mangoes | Apples | Oranges | Coconuts | Pomegranates |
| Number | 26 | 30 | 21 | 5 | 8 |
Represent the above data by a pie chart.
Answer 7:
Total number of fruits=(26+30+21+5+8)=90Central angle of each fruit=(number of each type of fruittotal number of fruits×360)°Calculation of central angles
| Types of fruit | Number | Central angle |
|---|---|---|
| Mangoes | 26 | 104° |
| Apples | 30 | 120° |
| Oranges | 21 | 84° |
| Coconuts | 5 | 20° |
| Pomegranates | 8 | 32° |
Construction of pie chartSteps of construction:1. Draw a circle of any convenient radius.2. Draw a horizontal radius of the circle.3. Draw sectors whose central angles are 104°, 120°, 84°, 20° and 32°.4. Shade the sectors so obtained differently and label each one of them.Thus, we obtain the required pie chart as shown in the figure below.
Q8 | Ex-24A | Class 8 | RS AGGARWAL | chapter 24 | Pie Charts
Question 8:
The following data shows the agricultural production in India during a certain year.
| Food grain | Rice | Wheat | Coarse cereals | Pulses |
| Production (in millions of tonnes) | 57 | 76 | 38 | 19 |
Draw a pie chart to represent the above data.
Answer 8:
Total production=(57+76+38+19)=190Central angle of each foodgrain=(production of each foodgraintotal production×360)°Calculation of central angles
| Food grain | production (in millions of tonnes) | Central angle |
|---|---|---|
| Rice | 57 | 108° |
| Wheat | 76 | 144° |
| Coarse cereals | 38 | 72° |
| Pulses | 19 | 36° |
Construction of pie chartSteps of construction:1. Draw a circle of any convenient radius.2. Draw a horizontal radius of the circle.3. Draw sectors whose central angles are 108°, 144°, 72° and 36°.4. Shade the sectors so obtained differently and label each one of them.Thus, we obtain the required pie chart as shown in the figure below.
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Q9 | Ex-24A | Class 8 | RS AGGARWAL | chapter 24 | Pie Charts
Question 9:
Given below is the result of an annual examination of a class, showing the percentage of students in each category.
| First division | Second division | Third division | Failed |
| 25% | 45% | 20% | 10% |
Represent the above data by a pie chart.
Answer 9:
Total percentage=100Central angle of each category=(value (in %) of each category100×360)°Calculation of central angles
| Category | Result (in %) | Central angle |
|---|---|---|
| First division | 25 | 90° |
| Second division | 45 | 162° |
| Third division | 20 | 72° |
| Failed | 10 | 36° |
Construction of pie chartSteps of construction:1. Draw a circle of any convenient radius.2. Draw a horizontal radius of the circle.3. Starting from the horizontal radius, draw sectors whose central angles are 90°, 162°, 72° and 36°.4. Shade the sectors so obtained differently and label each one of them.Thus, we obtain the required pie chart as shown in the figure below.
Q10 | Ex-24A | Class 8 | RS AGGARWAL | chapter 24 | Pie Charts
Question 10:
The following table shows the percentages of buyers of four different brands of bathing soaps.
| Brand | A | B | C | D |
| Percentage of buyers | 20% | 40% | 25% | 15% |
Represent the above data by a pie chart.
Answer 10:
Total percentage=100Central angle of each brand=(value (in %) of each brand 100×360)°Calculation of central angles:
| Brand | Buyers (in %) | Central angle |
|---|---|---|
| A | 20 | 72° |
| B | 40 | 144° |
| C | 25 | 90° |
| D | 15 | 54° |
Construction of pie chartSteps of construction:1. Draw a circle of any convenient radius.2. Draw a horizontal radius of the circle.3. Draw sectors whose central angles are 72°, 144°, 90° and 54°.4. Shade the sectors so obtained differently and label each one of them.Thus, we obtain the required pie chart as shown in the figure below.
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