Exercise 18C
Page-211
Q1 | Ex-18C | Class 8 | RS AGGARWAL | chapter 18 | Area of Trapezium and a Polygon
Question 1:
Tick (✓) the correct answer:
The parallel sides of a trapezium measure 14 cm and 18 cm and the distance between them is 9 cm. The area of the trapezium is
(a) 96 cm2
(b) 144 cm2
(c) 189 cm2
(d) 207 cm2
Answer 1:
(b) 144 cm2
Area of the trapezium={12×(14+18)×9} cm2
=(12×32×9) cm2=144 cm2
Q2 | Ex-18C | Class 8 | RS AGGARWAL | chapter 18 | Area of Trapezium and a Polygon
Question 2:
Tick (✓) the correct answer:
The lengths of the parallel sides of a trapezium are 19 cm and 13 cm and its area is 128 cm2. The distance between the parallel sides is
(a) 9 cm
(b) 7 cm
(c) 8 cm
(d) 12.5 cm
Answer 2:
(c) 8 cm
Let the distance between the parallel sides be x cm.Then, area of the trapezium={12×(19+13)×x} cm2
=(12×32×x) cm2=16x cm2
But it is given that the area of the trapezium is 128 cm2.
∴ 16x=128⇒x=12816⇒x=8 cm
Q3 | Ex-18C | Class 8 | RS AGGARWAL | chapter 18 | Area of Trapezium and a Polygon
Question 3:
Tick (✓) the correct answer:
The parallel sides of a trapezium are in the ratio 3 : 4 and the perpendicular distance between them is 12 cm. If the area of the trapezium is 630 cm2, then its shorter of the parallel sides is
(a) 45 cm
(b) 42 cm
(c) 60 cm
(d) 36 cm
Answer 3:
(a) 45 cm
Let the length of the parallel sides be 3x cm and 4x cm, respectively.Then, area of the trapezium={12×(3x+4x)×12} cm2
=(12×7x×12)cm2=42 x cm2
But it is given that the area of the trapezium is 630 cm2.
∴ 42x=630⇒x=63042⇒x=15 cm
Length of the parallel sides = (3×15)cm=45 cm (4×15) cm=60 cmHence, the shorter of the parallel sides is 45 cm.
Q4 | Ex-18C | Class 8 | RS AGGARWAL | chapter 18 | Area of Trapezium and a Polygon
Question 4:
Tick (✓) the correct answer:
The area of a trapezium is 180 cm2 and its height is 9 cm. If one of the parallel sides is longer than the other by 6 cm, the length of the longer of the parallel sides is
(a) 17 cm
(b) 23 cm
(c) 18 cm
(d) 24 cm
Answer 4:
(b) 23 cm
Let the length of the parallel sides be x cm and (x+6) cm, respectively.Then, area of the trapezium={12×(x+x+6)×9} cm2
={12×(2x+6)×9} cm2=4.5(2x+6) cm2=(9x+27) cm2
But it is given that the area of the trapezium is 180 cm2.∴ 9x+27=180⇒9x=(180-27)⇒9x=153⇒x=1539⇒x=17Therefore, the length of the parallel sides are 17 cm and (17+6) cm, which is equal to 23 cm.Hence, the length of the longer parallel side is 23 cm.
Q5 | Ex-18C | Class 8 | RS AGGARWAL | chapter 18 | Area of Trapezium and a Polygon
Question 5:
Tick (✓) the correct answer:
In the given figure, AB||DC and DA ⊥ AB. If DC = 7 cm, BC = 10 cm, AB = 13 cm and CL ⊥ AB, the area of trap. ABCD is
(a) 84 cm2
(b) 72 cm2
(c) 80 cm2
(d) 91 cm2
Answer 5:
(c) 80 cm2
From the given trapezium, we find:DC=AL=7 cm [since DA⊥AB and CL⊥AB]From the right ∆CBL, we have: CL2=CB2-LB2⇒CL2=(10)2-(6)2⇒CL2=100-36⇒CL2=64⇒CL=√64⇒CL=8 cmArea of the trapezium={12×(7+13)×8} cm2
=(12×20×8) cm2=80 cm2
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