RS Aggarwal solution class 8 chapter 10 Profit and Loss Exercise 10B

Exercise 10B

Page-138

Q1 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 1:

The marked price of a water cooler is Rs 4650. The shopkeeper offers an off-season discount of 18% on it. Find its selling price.

Answer 1:

Marked price = Rs 4650 and discount = 18%
Discount = 18% of marked price
              =18% of Rs 4650
             =Rs 4650×18100=Rs 837
Selling price = marked price − discount
                     =Rs (4650 - 837)=Rs 3813

Therefore, the selling price of the cooler is Rs 3813.


Q2 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 2:

The price of a sweater was slashed from Rs 960 to Rs 816 by a shopkeeper in the winter season. Find the rate of discount given by him.

Answer 2:

Marked Price = Rs 960
Selling Price = Rs 816
Discount = MP − SP
                = Rs (960 − 816)
                  = Rs 144
Rate of discount=144×100960=15%

Therefore, the discount on the sweater is 15%.


Q3 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 3:

Find the rate of discount being given on a shirt whose selling price is ₹ 1092 after deducting a discount of ₹ 208 on its marked price.

Answer 3:

SP of the shirt = ₹1,092
Discount = ₹208
MP = SP + Discount = ₹1,092 + ₹208 = ₹1,300
∴ Rate of discount = DiscountMP×100%=2081300×100%=16%


Q4 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 4:

After allowing a discount of 8% on a toy, it is sold for Rs 216.20. Find the marked price of the toy.

Answer 4:

Selling Price = Rs 216.20
Rate of discount = 8%
Marked Price = ?
SP = MP − discount
Let the MP be Rs x.

Now, x-8100×x=216.2092x100=216.2092x=21620x=2162092x=235

∴ Marked price = Rs 235


Q5 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 5:

A tea set was bought for Rs 528 after getting a discount of 12% on its marked price. Find the marked price of the tea set.

Answer 5:

Cost price = Rs 528
Rate of discount = 12%
Marked price = ?
SP= MP − discount
Let the MP be Rs x.
Now, x-12100×x=52888x100=52888x=52800x=5280088x=Rs 600

Therefore, the marked price of tea set is Rs 600.


Q6 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 6:

A dealer marks his goods at 35% above the cost price and allows a discount of 20% on the marked price. Find the gain or loss per cent.

Answer 6:

Let Rs 100 be the CP.
Then, marked price = Rs 135
Discount = 20% of MP
                =20100×135=27
Selling price = marked price − discount
                     = 135 − 27
                     = Rs 108
Now, gain = SP − CP
                  =108 − 100
                   =Rs 8

 Gain percentage=gainCP×100

                            = 8100×100= 8%


Q7 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 7:

A cellphone was marked at 40% above the cost price and a discount of 30% was given on its marked price. Find the gain or loss per cent made by the shopkeeper.

Answer 7:

Let Rs 100 be the CP.
Then, marked price = Rs 140
Discount = 30% of MP
                =30100×140=42
Selling Price = marked price − discount
                      = 140 − 42
                      = Rs 98
Now, loss = CP − SP
                 = 100 − 98
                 = Rs 2
 Loss percentage=Loss×100CP=2×100100=2%

Therefore, the shopkeeper had a loss of 2%.


Q8 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 8:

A dealer purchased a fan for Rs 1080. After allowing a discount of 25% on its marked price, he gains 25%. Find the marked price of the fan.

Answer 8:

Cost price of the fan = Rs 1080
Gain percentage = 25%
 Selling price = (100 +gain %)100×CP=100+25100×1080=125100×1080=Rs 1350

Let the marked price be Rs x.
Discount = 25% of Rs x

             =25x100

SP = MP − discount
⇒ 1350 = X − 25X100

1350=100x-25x100135000=75x x=1350075 x=1800

Therefore, the marked price of the fan is Rs 1800.


Q9 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 9:

A dealer bought a refrigerator for Rs 11515. After allowing a discount of 16% on its marked price, he gains 20%. Find the marked price of the refrigerator.

Answer 9:

Cost price of the refrigerator = Rs 11515
Gain percentage = 20%.
 Selling price =(100 +gain %)100×C.P=100+20100×11515=120100×11515=Rs 13818

Let the marked price be Rs x.
Discount = 16% of Rs x
                =16x100
S.P = MP − Discount
⇒ 13818 = x − 16x100

13818=100x-16x1001381800=84x x=138180084 x=16450

​Therefore, the marked price of the refrigerator is Rs 16450.


Q10 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 10:

A jeweller allows a discount of 16% to his customers and still gains 20%. Find the marked price of a ring which costs the jeweller Rs 1190.

Answer 10:

The cost price of the ring is Rs 1190.
Gain percentage = 20%.
 Selling price =(100 +gain %)100×C.P=100+20100×1190=120100×1190=Rs 1428

Let the marked price be x.
Discount = 16% of Rs x
               =16x100
SP = MP − Discount

1428=x-16x1001428=100x-16x100142800=84x14280084=xx=1700

​Therefore, the marked price of the ring is Rs 1700.


Q11 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 11:

After allowing a discount of 10% on the marked price, a trader still makes a gain of 17%. By what per cent is the marked price above the cost price?

Answer 11:

Let Rs 100 be the cost price.
Gain required = 17%
∴ Selling price = Rs 117
Let the marked price be Rs x.
Then, discount = 10% of x
                        =10100×x=x10
Selling Price = MP − discount
117=x-x10117=9x10

9x=1170x=11709x=130

∴ Marked price = Rs 130

Hence, the marked price is 30% above the cost price.


Q12 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 12:

How much per cent above the cost price should a shopkeeper mark his goods so that after allowing a discount of 10% on the marked price, he gains 8%?

Answer 12:

Let Rs 100 be the cost price.
Gain required = 8%
Therefore, the selling price is Rs 108.
Let Rs x be the marked price.
Then, discount = 10% of x
                      =10100×x=x10
Selling Price = MP − discount
117=x-x10117=9x10

9x=1080x=10809x=120

∴ Marked price = Rs 120

Hence, the marked price is 20% above the cost price.


Q13 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 13:

The marked price of a TV is Rs 18500. A dealer allows two successive discounts of 20% and 5%. For how much is the TV available?

Answer 13:

Marked price of the TV = Rs 18500
First discount = 20%

Now, 20% of 18500=20100×18500=Rs 3700

Price after the first discount = Rs (18500 − 3700)= Rs 14800
Second discount = 5% of 14800
                                =5100×14800=740
Price after the second discount = (14800 − 740)
                                                   = Rs 14060
The TV is available for Rs 14060.


Q14 | Ex-10B | Class 8 | RS AGGARWAL | chapter 10 | Profit and Loss | myhelper

Question 14:

Find the single discount which is equivalent to two successive discounts of 20% and 5%.

Answer 14:

​Let the marked price of the article be Rs 100.
First discount = 20%
Price after the first discount = (100 − 20) = Rs 80
Second discount = 5% of 80
                            =5100×80=Rs 4
Price after the second discount = (80 − 4) = Rs 76
Net selling price = Rs 76
∴ Single discount equivalent to the given successive discounts = (100 − 76)% = 24%

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