RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Exercise 3C

     

EXERCISE-3C

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Question 1

Q.1. Perform the following subtractions. Check your results by the corresponding additions:

(i) 6237 - 694

(ii) 21205 - 10899

(iii) 100000 - 78987

(iv) 1010101 - 656565

Ans.

<to be added>

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Question 2

Q.2. Replace each * by the correct digit in each of the following :
(i) $\begin{array}{r}917 \\ -* 5 * \\ \hline 5 * 8 \\ \hline\end{array}$
(ii) $\begin{array}{r}6172 \\ -* * 69 \\ \hline 29 * * \\ \hline\end{array}$
(iii) $\begin{array}{r}5001003 \\ -* * 6987 \\ \hline 484 * * * * \\ \hline\end{array}$
(iv) $\begin{array}{r}1000000 \\ -* * * * 1 \\ \hline * 7042 * \\ \hline\end{array}$

Ans.
(i) $\begin{array}{r}917 \\ -359 \\ \hline 558 \\ \hline\end{array}$
(ii) $\begin{array}{r}6172 \\ -3269 \\ \hline 2903 \\ \hline\end{array}$
(iii) $\begin{array}{r}5001003 \\ -156987 \\ \hline 4844016 \\ \hline\end{array}$
(iv) $\begin{array}{r}1000000 \\ -29571 \\ \hline 970429 \\ \hline\end{array}$

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Question 3

Q.3. Find the difference :
(i) 463 - 9
(ii) 5632 - 99
(iii) 8640 - 999
(iv) 13006 - 9999

Ans. 

(i) $463-9=464-1-9=464-10$ $=454$

(ii) $5632-99=5632-100+1$
$=5633-100=5533$

(iii) $8640-999=8640-1000+1$
$=8641-1000=7641$

(iv) $13006-9999=13006-10000+1$
$=13007-10000=12007$

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Question 4

Q.4. Find the difference between the smallest number of 7 digits and the largest number of 4 digits.

Ans. Smallest number of 7-digits $=1000000$
Largest number of 4-digits $=9999$
Required difference $=(1000000-9999)$
$=990001$

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Question 5

Q.5. Ravi opened his account in a bank by depositing Rs. 136000. Next day he withdrew Rs. 73129 from it. How much money was let in his account?
Ans. Deposit in the beginning = Rs. 136000
Next day withdrew = Rs. 73129
$\therefore$ Amount left in the bank account
=Rs. $136000-73129=$ Rs. 62871

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Question 6

Q.6. Mrs Saxena withdrew Rs. 100000 from her bank account. She purchased a TV set for Rs. 38750, a refrigerator for Rs. 23890 and jewellery worth Rs. 35560 . How much money was left with her?

Ans. Amount withdrawn from the bank
= Rs. 1,00,000
Cost of TV set = Rs. 38750
Cost of refrigerator $=$ Rs. 23890
Cost of jewellery $=$ Rs. 35560
Total amount spent on her purchase

$\begin{aligned}
& =\text { Rs. }(38750+23890+35560) \\
& =\text { Rs. } 98200
\end{aligned}$

Amount left with her $=$ Rs. 1,00,000-
Rs. $98200=$ Rs. 1800

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Question 7

Q.7. The population of a town was 110500 . In one year it increased by 3608 due to new births. However 8973 persons died or left the town during the year. What was the population at the end of the year?

Ans. Population of a town $=110500$
Increase in 1 year $=3608$
Persons left or died $=8973$
$\therefore$ The population at the end of year
$\begin{aligned}
& =110500+3608-8973 \\
& =114108-8973=105135
\end{aligned}$

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Question 8

Q.8. Find the whole number n when :
(i) $n+4=9$
(ii) $\mathbf{n}+\mathbf{3 5}=101$
(iii) $\mathrm{n}-18=39$
(iv) $n-20568=21403$

Ans. (i) We have $n+4=9$
$\begin{aligned}
& n=9-4=5 \\
& \therefore n=5
\end{aligned}$

(ii) $n+35=101$
Subtracting 35 from both sides
$\begin{aligned}
& \mathrm{n}+35-35=101-35 \Rightarrow \mathrm{n}=66 \\
& \therefore \mathrm{n}=66
\end{aligned}$

(iii) $\mathrm{n}-18=39$
Adding 18 to both sides
$\begin{aligned}
& \mathrm{n}-18+18=39+18 \\
& \Rightarrow \mathrm{n}=57 \\
& \therefore \mathrm{n}=57
\end{aligned}$

(iv) $\mathrm{n}-20568=21403$
Adding 20568 to both sides
$\begin{aligned}
& n-20568+20568=21403+20568 \\
& n=41971
\end{aligned}$