RS Aggarwal Solutions Class 6 Chapter 2 Factors And Multiples Exercise 2C

    

EXERCISE-2C


Question 1
Find the prime factorization of each of the following numbers.
12 
Ans. We have

$
\begin{array}{l|r}
2 & 12 \\
\hline 2 & 6 \\
\hline 3 & 3 \\
\hline & 1
\end{array}
$

$\therefore 12=2 \times 2 \times 3=2^2 \times 3 \text {. }$


Question 2

18
Sol :
We have
$\begin{array}{l|c}
2 & 18 \\
\hline 3 & 9 \\
\hline 3 & 3 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 18=2 \times 3 \times 3 \\
& =2 \times 3^2 .
\end{aligned}$



Question 3
48
Ans. 
We have
$\begin{array}{l|r}
2 & 48 \\
\hline 2 & 24 \\
\hline 2 & 12 \\
\hline 2 & 6 \\
\hline 3 & 3 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 48=2 \times 2 \times 2 \times 2 \times 3 \\
& =2^4 \times 3
\end{aligned}
$


Question 4
56.
Ans. 
We have
$\begin{array}{l|r}
2 & 56 \\
\hline 2 & 28 \\
\hline 2 & 14 \\
\hline 7 & 7 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 56=2 \times 2 \times 2 \times 7 \\
& =2^3 \times 7 .
\end{aligned}
$


Question 5
90
Ans. 
We have
$\begin{array}{l|r}
2 & 90 \\
\hline 3 & 45 \\
\hline 3 & 15 \\
\hline 5 & 5 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 90=2 \times 3 \times 3 \times 5 \\
& =2 \times 3^2 \times 5
\end{aligned}
$



Question 6
136 
Ans. 
We have
$\begin{array}{r|r}
2 & 136 \\
\hline 2 & 68 \\
\hline 2 & 34 \\
\hline 17 & 17 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 136=2 \times 2 \times 2 \times 17 \\
& =2^3 \times 17
\end{aligned}
$


Question 7

252
Ans. 
We have
$\begin{array}{l|r}
2 & 252 \\
\hline 2 & 126 \\
\hline 3 & 63 \\
\hline 3 & 21 \\
\hline 7 & 7 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 252=2 \times 2 \times 3 \times 3 \times 7 \\
& =2^2 \times 3^2 \times 7
\end{aligned}
$


Question 8

420
Ans. 
We have
$\begin{array}{r|r}
2 & 420 \\
\hline 2 & 210 \\
\hline 3 & 105 \\
\hline 5 & 35 \\
\hline 7 & 7 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 420=2 \times 2 \times 3 \times 5 \times 7 \\
& =2^2 \times 3 \times 5 \times 7
\end{aligned}
$


Question 9

637
Ans.
We have
$\begin{array}{r|r}
7 & 637 \\
\hline 7 & 91 \\
\hline 13 & 13 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 637=7 \times 7 \times 13 \\
& =7^2 \times 13
\end{aligned}
$


Question 10

945Ans.
We have
$\begin{array}{r|r}
3 & 945 \\
\hline 3 & 315 \\
\hline 3 & 105 \\
\hline 5 & 35 \\
\hline 7 & 7 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 945=3 \times 3 \times 3 \times 5 \times 7 \\
& =3^3 \times 5 \times 7
\end{aligned}
$



Question 11

1224 
Ans. 
We have
$\begin{array}{r|r}
2 & 1224 \\
\hline 2 & 612 \\
\hline 2 & 306 \\
\hline 3 & 153 \\
\hline 3 & 51 \\
\hline 17 & 17 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 1224=2 \times 2 \times 2 \times 3 \times 3 \times 17 \\
& =2^3 \times 3^2 \times 17
\end{aligned}
$


Question 12

1323
Ans. 
We have
$\begin{array}{l|r}
3 & 1323 \\
\hline 3 & 441 \\
\hline 3 & 147 \\
\hline 7 & 49 \\
\hline 7 & 7 \\
\hline & 1
\end{array}$


$
\begin{aligned}
& \therefore 1323=3 \times 3 \times 3 \times 7 \times 7 \\
& =3^3 \times 7^2
\end{aligned}
$


Question 13

8712 
Ans. 
We have
$\begin{array}{r|r}
2 & 8712 \\
\hline 2 & 4356 \\
\hline 2 & 2178 \\
\hline 3 & 1089 \\
\hline 3 & 363 \\
\hline 11 & 121 \\
\hline 11 & 11 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 8712=2 \times 2 \times 2 \times 3 \times 3 \times 11 \times 11 \\
& =2^3 \times 3^2 \times 11^2 .
\end{aligned}
$


Question 14
 9317 
Ans. 
We have
$\begin{array}{r|r}
7 & 9317 \\
\hline 11 & 1331 \\
\hline 11 & 121 \\
\hline 11 & 11 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 9317=7 \times 11 \times 11 \times 11 \\
& =7 \times 11^3
\end{aligned}
$


Question 15

1035
Ans.
We have
$\begin{array}{r|r}
3 & 1035 \\
\hline 3 & 345 \\
\hline 5 & 115 \\
\hline 23 & 23 \\
\hline & 1
\end{array}$


$
\begin{aligned}
& \therefore 1035=3 \times 3 \times 5 \times 23 \\
& =3^2 \times 5 \times 23
\end{aligned}
$


Question 16

1197 
Ans. 
We have
$\begin{array}{r|r}
3 & 1197 \\
\hline 3 & 399 \\
\hline 7 & 133 \\
\hline 19 & 19 \\
\hline & 1
\end{array}$

$
\begin{aligned}
& \therefore 1197=3 \times 3 \times 7 \times 19 \\
& =3^2 \times 7 \times 19
\end{aligned}
$


Question 17

 4641
Ans. 
We have
$\begin{array}{r|r}
3 & 4641 \\
\hline 7 & 1547 \\
\hline 13 & 221 \\
\hline 17 & 17 \\
\hline & 1
\end{array}$

$
\therefore 4641=3 \times 7 \times 13 \times 17 .
$


Question 18

 4335 
Ans. 
We have
$\begin{array}{r|r}
3 & 4335 \\
\hline 5 & 1445 \\
\hline 17 & 289 \\
\hline 17 & 17 \\
\hline & 1
\end{array}$
$\therefore 4335=3 \times 5 \times 17 \times 17=3 \times 5 \times 17^2$.




Question 19

2907
Ans. 
We have
$\begin{array}{r|r}
3 & 2907 \\
\hline 3 & 969 \\
\hline 17 & 323 \\
\hline 19 & 19 \\
\hline & 1
\end{array}$


$
\therefore 2907=3 \times 3 \times 17 \times 19=3^2 \times 17 \times 19 .$


Question 20 
13915 
Ans. We have
$\begin{array}{r|r}
5 & 13915 \\
\hline 11 & 2783 \\
\hline 11 & 253 \\
\hline 23 & 23 \\
\hline & 1
\end{array}$

$
\therefore 13915=5 \times 11 \times 11 \times 23=5 \times 11^2 \times 23
$

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