SChand Composite Mathematics Class 7 Chapter 9 Percentage and it's application Exercise 9A

  Exercise 9A


Q1 | Ex-9A | Class 7 | SChand Composite Maths | Percentage and it's application | myhelper

OPEN IN YOUTUBE 



Question 1 

Name each of fraction as percent: 

(i) 3100
Sol: 3%

(ii) 29100
Sol: 29% 

(iii)  151100
Sol: 151%

(iv)  12.5100 
Sol: =12.5%

(v) 235100 
Sol: 235% 



Q2 | Ex-9A | Class 7 | SChand Composite Maths | Percentage and it's application | myhelper

OPEN IN YOUTUBE 


Question 2

Express each of the following as a fraction in Simplest form: 

(i) 25% 
Sol: 25100=14

(ii) 625% 
Sol: 625100
254614

(iii) 3312%
Sol: =672%=67200

(iv) 6623%
Sol: 2003%=200300=23
 
(v) 9.2% 
Sol: 921000=23250

(vi) 18.75 % 
Sol: 18.75100
=1875100×100
=316



Q3 | Ex-9A | Class 7 | SChand Composite Maths | Percentage and it's application | myhelper

OPEN IN YOUTUBE 


Question 3

Convert each of the following Percent into decimal: 

(i) 27% 
Sol: 27100=0.27

(ii) 8%
Sol:  8100=0.08

(iii) 130%
Sol: 130100=1.3

(iv) 69% 
Sol: 69.5100=0.695 

(v) 3.68%
Sol: 3.68100=0.0368

(vi) 0.0208%
Sol: 0.0208100=0.000208



Q4 | Ex-9A | Class 7 | SChand Composite Maths | Percentage and it's application | myhelper

OPEN IN YOUTUBE 


Question 4

Express the following fractions as Percent:

(i)  12×100
Sol: 50%
= 50100=12

(ii) 1725×100
Sol: 68% 

(iii) 38×100
Sol: 752=37.5%

(iv) 2716
Sol: 3916×100
9754=243.75%

(v) 1475=×100
Sol: 563=1823%

(vi) 23
Sol: 23×100
=6623%



Q5 | Ex-9A | Class 7 | SChand Composite Maths | Percentage and it's application | myhelper

OPEN IN YOUTUBE 


Question 5

Convert the following decimals into percent: 

(i) 0.58×100
Sol: 5.8%

(ii) 0.6×100
Sol: 60%

(iii) 0.039×100
Sol: 3.9%

(iv) 0.708 ×100
Sol: 70.8%

(v) 2.05×100
Sol: = 205%

(vi) 0.001×100
Sol: 0.1%



Q6 | Ex-9A | Class 7 | SChand Composite Maths | Percentage and it's application | myhelper

OPEN IN YOUTUBE 


Question 6

Find the value of: 

(i)  20% of 650
Sol: 26100×650
=130 answer 

(ii) 140% of 75
Sol: 140100×75
35×3
=105Ans

(iii) 25% of 18
 Sol: 25100×18
=14×18
=132

(iv) 4.5% of 60cm 
Sol: =4.5100×10×60
=2710=2.7 cm

(v) 712% of 56
Sol: 152×100×56
=4210=Rs4.2

(vi) 60% of 1 year 
Sol: 60100×365
=219 days 



Q7 | Ex-9A | Class 7 | SChand Composite Maths | Percentage and it's application | myhelper

OPEN IN YOUTUBE 


Question 7

What percent is : 

(i) 25 of 60 

Sol: 2560×100=2506=4146

(ii) 7.5 of 150 
Sol: 7.5150×100
= 5% answer 

(iii) 5 paise of Rs 5 
Sol: 5500×100=1%

(iv) 212 cm of 10 cm
Sol:  2.510×100=25%

(v) 55m to 1 km 
Sol: 1km = 1000m
=551000×100
=5.5 %

(vi) 40 sec of 2min 40 sec 

Sol: 40160×100
= 25% 




Q8 | Ex-9A | Class 7 | SChand Composite Maths | Percentage and it's application | myhelper

OPEN IN YOUTUBE 


Question 8

Find the number whose: 

(i) 14 % is 28 
Sol: Let the number is x
=14 % of x = 28 = 14100×x=28
=  x=28×10014=200 Answer 
 
(ii) 1623% is 3
Sol: 50300×x=3x=3×305
x=18 answer 



Q9 | Ex-9A | Class 7 | SChand Composite Maths | Percentage and it's application | myhelper

OPEN IN YOUTUBE 


Question 9

What is the length whose 30 % is 24 cm ?

Sol: Let the length be x 
30%ofx=2430100×x=24
=x =24×10030
x= 80 answer 

(ii) What is the volume of whose 1623% is 0.75 L ? 

Sol: 
503÷100×x=75100
503×1100×x=75100
x6=75100
x=75100×6
x=450100=4.5 L




Q10 | Ex-9A | Class 7 | SChand Composite Maths | Percentage and it's application | myhelper

OPEN IN YOUTUBE 

Question 10

What is the % change when 
(i) 25 is increased to 45 
Change = 45-25= 20
%Increase =  AmountincreaseOriginalamount×100
2025×100=80%

(ii) 200 is decreased to 190 
Decrease = 200- 190 = 10 
% Decrease = 10200×100
=5%

(iii) 64 is increased to 144 
Increase = 14 -64 = 80 
% Increase =  8064×100=10008=125%

(iv) 320 is decreased to 288
Decrease = 320 - 288= 32
% Decrease = 32320×100
=10%



Q11 | Ex-9A | Class 7 | SChand Composite Maths | Percentage and it's application | myhelper

OPEN IN YOUTUBE 

 
Question 11

Increase 

(i) Rs 80 by 5% 
Sol: 5% Of 80 = Amount of increase 
5100×80=Rs4

∴ Increased amount = Original + Increase 
=80+4=Rs84

(ii) 440 By 80 %

Sol: Increase = 80 % of 440 = 80100×440
= 352
∴   Increase amount  = 440+ 352 = Rs 792 answer 

(iii) Rs 120 By 3313%
 Sol: Increase = 1003%of120
100300×120
= Rs 40 
∴   Increase amount  =  120 + 40 = Rs 160 Answer 

(iv) 44 by 2.5 % 

Sol: Increase  = 2.5 % of 44 = 1.1
∴   Increase amount   = 44+ 1.1= 45.1 Answer



Q12 | Ex-9A | Class 7 | SChand Composite Maths | Percentage and it's application | myhelper

OPEN IN YOUTUBE 


Question 12

Decrease : 

(i) 400 by 25% 

Decrease % = 25% of 400 = 25100×400=100

Total 
Decrease = Original - Decrease 
400- 100= 300 answer 

(ii) Rs 8 by 12 % 

Decrease % = 12% of 8 
=96100=0.96
Decrease amount = 8- 0.96 = Rs 7.04 answer

(iii) 150 by 3313%
Sol: Decrease %= 1003%of150= 1003×100×150 =50

Decrease = 150 -50 = 100 answer 

(iv) 500 by 12.5%

Sol: Decrease % = 12.5% of 500
12.5100×500=62.5

Decrease amount = 50062.5
= 437.5 answer 


No comments:

Post a Comment

Contact Form

Name

Email *

Message *