Exercise 14 G
Question 1
Ans: (i) Draw a circle with center O and A suitable radius.
(ii)Take of point P outside the circle.
(iii) Join OP and take its midpoint M.
(iv) with center mand diameter op, draw a circle which intersects the given circle at T and S
(V) Join PT and PS.
PT and PS are required tangents to the circle on measuring PT=PS=5.5 cm
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Question 2
Ans: (i) Draw a circle with center O and with a suitable radius
(ii) Take a point P on it and Join OP .
(iii) At P draw a perpendicular to op which meet a given line at S
Then ST is the required tangent.
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Question 3
Ans: (i) Draw a circle with center O and radius 4 cm.
(ii) Take a point P Such that OP= 5cm
(iii)Draw its bisector which bisects OP =5cm
(iv) With center M and radius MP draw a circle intersecting the given circle at T and S.
(v) Join PT and PS.
PT and PS are the required tangents to the circle on Measuring each of them PT=PS=3cm
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Question 4
Ans: (i) Draw a circle with center O and radius 2cm
(ii) Take a point P outside the circle
(iii) From P draw a straight line which intersects the circle at A and B
(iv) With BP as diameter draw a semicircle
(v) At A, draw a perpendicular which meets the semicircle at c
(vi) With center P and radius PC, draw an arc which intersects the given circle at T and S.
(vii) Join PT.
PT is the required tangent.
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Question 5
Ans:( i) Draw a circle with center O and some suitable radius.
(ii) Take a point P on it.
(iii) Take two more points Q and R on the remaining part of the circle and Joined PQ,QR and RP.
(iv) Draw an angle ∠QPT equal to ∠R and Produce the line TP to S.
Then SPT is the required tangent to the circle
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Question 6
Ans: (i) Draw a circle with center O and a suitable radius.
(ii) Draw a radius OS and on PS, draw an angle ∠SOT of 180∘−60∘=120∘
(iii) At S and T draw lines making 90∘ each. which intersect each other at P
Then PT and SP are the required tangents making an angle of 60 with each other at P on measuring them each one of them is 4.5cm
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Calculation :
Here radius of the circle (r)= 3cm and distance of OP= 5.3cm
In right △OPT,
PT2=OP2−OT2=(5.3)2−(3)2
=28.09−9= (9.09)= (4.37)2
So PT=4.37 cm
Question 7
Ans: (i) Draw a line segment AC=7 cm(b=7 cm)
(ii) At C, draw a ray CX making an angle of 30∘
(iii) With center A and Radius 6cm(c= 6cm) Draw are which intersects CX at B and B'
(iv) Join AB and AB'
Then two triangle are possible △ABC and △AB′C in which a= 1.3cm or 11.3cm
(v) Now draw the perpendicular bisector of AC and BC which intersect each other at O.
(vi) With center O and radius equal to OB, Draw a circle which passes through A,B and C,
Then this is the required circumcircle of the △ABC. on measuring its radius =6.5 cm
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Question 8
Ans: (i) Draw a line segment BC = 6cm
(ii) At B, draw a ray BX making an angle of 90∘ and cut off BA=4 cm
(iii) Join AC.
(iv) Now draw the perpendicular bisects of AB and DC intersecting each other at O.
(V) With center O and radius OA, draw a circle which will pass through A,B and C.
This is required circumcircle of △ABC Whose radiues is 12AC=3.6 cm
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Question 9
Ans: Steps of constructions:
(i) Draw a line segment BC=4 cm
(ii) At C, draw a ray CX making a angle of 45 and CY making an angle of 90
(iii) Cut off CQ = 2.5cm
(iv) From Q, draw a line PQ parallel to BC. Which meets CX at A.
(v) Join A B
(vi) Draw the perpendicular bisects of AB and BC which intersects each other at O.
(vii) With center O and radius OA, draw a circle which will pass through A,B and C.
This is the required circumcircle of △ABC Whose radius OA= 2.1cm
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Question 10
Ans: It is true
Question 11
Ans: (i) Draw a line segment BC = 4cm
(ii) With center B and C and Radius 4cm , draw arcs which intersect each other at A.
(iii) Join AB and CA .
Then △ABC is an equilateral triangle
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(iv) Draw the perpendicular bisects of sides AB and BC which intersect each other at O.
(v) with center O and radius OA, draw a circle which will pass through A,B, C .
Question 12
Ans: Steps of construction:
(i) Draw the given △ABC.
(ii) Draw the angle bisects of ∠B and ∠C which intersects each other at I.
(iii) From I . Draw a perpendicular ID and BC.
(iv) with Center I and radius ID, draw a circle which touches the sides of the triangle ABC at D,E and F.
On measuring the radius ID=1.4cm
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Question 13
Ans: (i)Draw the line segment BC =5cm
(ii) with centers B and C and radius 5 cm, draw arcs intersecting each other at A.
(iii) Join AP and AC.
△ABC is an equilateral triangle.
(iv) Draw the angle bisectors of ∠B and ∠C which intersect each other at 1 .
(v) From 1. draw ID ⊥BC.
(vi) With center I and radius ID draw a circle which will the sides of △ABC at DE and F.
On measuring the radius ID = 1.5cm
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Question 14
Ans: (a) (i) Draw a line segment AB = 8cm
(ii) With center A and Radius 5cm and With center B and Radius 6cm Draw arcs Which intersect each other At C.
(iii) Join AC and BC.
△ABC is the required mangle.
(b) (i) Draw the bisector of ∠A and ∠B Which intersect each other at I. I is the incenter of the in circle
(c) (ii) From L, cut off LP=LQ=1 cm So that PQ = 2cm
(iii) With center I and Radius IP Draw a circle which intersects BC at R and S CA at T and U.
Then chords PQ= RS= TU =2cm.
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Question 15
Ans: ( i) Draw a line segment AB=3.2 cm.
(ii) Draw rays at A and B making angle of 120∘ each and cut off AF=BC=3.2 cm
(iii) Similarly at F and C, draw rays making angle of 120 each and cut off FE =CD = 3.2cm
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(iv) Join ED
ABCDEf is a regular hexagon.
(v) Draw the angle bisects of ∠A and ∠B which intersect each other at O .
(vi) From O, draw QL⊥ AB
(vii) with center O and radius OL draw a circle which will touch the sides regular of regular hexagon ABCDEF.
Question 16
Ans: (i) Draw a line segment AB=2.8 cm
(ii) At A and B draw rays making angle of 120∘ each and cut off AF=BC=2.8 cm
(iii) similarly at F and C,draw rays making angle of 120∘ and we Cut FE=CD=2.8 cm
(iv) Join ED.
ABCDEF is a regular hexagon.
(v) Draw the perpendicular bisects of AB and AF which intersect each other at O.
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