RS AGGARWAL CLASS 9 CHAPTER 7 LINES AND ANGLES EXERCISE 7B

 EXERCISE 7B

PAGE NO-206

Question 1:

In the adjoining figure, AOB is a straight line. Find the value of x.






Answer 1:

We know that the sum of angles in a linear pair is 180°.
Therefore,
AOC+BOC=180°62°+x°=180°x°=180°-62°x=118°
Hence, the value of x is 118°.

Question 2:

In the adjoining figure, AOB is a straight line. Find the value of x. Hence, find ∠AOC and ∠BOD.









Answer 2:

As AOB is a straight line, the sum of angles on the same side of AOB, at a point O on it, is 180°.
Therefore,
 AOC+COD+BOD=180°3x-7°+55°+x+20°=1804x=112°x=28°
Hence,
AOC=3x-7
         =3×28-7=77°
and BOD=x+20
                =28+20=48°

PAGE NO-207

Question 3:

In the adjoining figure, AOB is a straight line. Find the value of x. Also, find ∠AOC, ∠COD and ∠BOD.








Answer 3:

AOB is a straight line. Therefore,
AOC+COD+BOD=180°3x+7°+2x-19°+x°=180°6x=192°x=32°
Therefore,
AOC=3×32°+7=103°COD=2×32°-19=45° andBOD=32°

Question 4:

In the adjoining figure, x:y:z = 5:4:6. If XOY is a straight line, find the values of x, y and z.








Answer 4:

Let x=5a, y=4a and z=6a
XOY is a straight line. Therefore,

XOP+POQ+YOQ=180°5a+4a+6a=180°15a=180°a=12°
Therefore,

      x5×12°=60°      y4×12°=48°and z6×12°=72°

Question 5:

In the adjoining figure, what value of x will make AOB a straight line?







Answer 5:

AOB will be a straight line if
3x+20+4x-36=180°7x=196°x=28°
Hence, x = 28 will make AOB a straight line.

Question 6:

Two lines AB and CD intersect at O. If ∠AOC = 50°, find ∠AOD, ∠BOD and ∠BOC.





Answer 6:

We know that if two lines intersect then the vertically-opposite angles are equal.
Therefore, AOC=BOD=50°
Let AOD=BOC=x°
Also, we know that the sum of all angles around a point is 360°.
Therefore, 
AOC+AOD+BOD+BOC=360°50+x+50+x=360°2x=260°x=130°
Hence, AOD=BOC=130°
Therefore, AOD=130°, BOD=50° and BOC=130°.

Question 7:

In the adjoining figure, three coplanar lines AB, CD and EF intersect at a point O, forming angles as shown. Find the values of x, y, z and t.












Answer 7:

We know that if two lines intersect, then the vertically opposite angles are equal.
BOD=AOC=90°
Hence, t=90°
Also, 
DOF=COE=50°
Hence, z=50°
Since, AOB is a straight line, we have:
AOC+COE+BOE=180°90+50+y=180°140+y=180°y=40°
Also,
BOE=AOF=40°
Hence, x=40°
 x=40°, y=40°, z=50° and t=90°

Question 8:

In the adjoining figure, three coplanar lines AB, CD and EF intersect at a point O. Find the value of x. Also, find ∠AOD, ∠COE and ∠AOE.






Answer 8:

We know that if two lines intersect, then the vertically-opposite angles are equal.
DOF=COE=5x°AOD=BOC=2x° andAOE=BOF=3x°

Since, AOB is a straight line, we have:
AOE+COE+BOC=180°3x+5x+2x=180°10x=180°x=18°

Therefore,
AOD=2×18°=36°COE=5×18°=90°AOE=3×18°=54°

Question 9:

Two adjacent angles on a straight line are in the ratio 5 : 4. Find the measure of each of these angles.

Answer 9:

Let the two adjacent angles be 5x and 4x, respectively.
Then,
5x+4x=180°9x=180°x=20°
Hence, the two angles are 5×20°=100° and 4×20°=80°.

Question 10:

If two straight lines intersect in such a way that one of the angles formed measures 90°, show that each of the remaining angles measures 90°.

Answer 10:

We know that if two lines intersect, then the vertically-opposite angles are equal.

AOC=90°. Then, AOC=BOD=90°.
And let BOC=AOD=x
Also, we know that the sum of all angles around a point is 360°
AOC+BOD+AOD+BOC=360°90°+90°+x+x=360°2x=180°x=90°
Hence, BOC=AOD=90°
AOC=BOD=BOC=AOD=90°
Hence, the measure of each of the remaining angles is 90o.



PAGE NO-208

Question 3:

In the adjoining figure, AOB is a straight line. Find the value of x. Also, find ∠AOC, ∠COD and ∠BOD.








Answer 3:

AOB is a straight line. Therefore,
AOC+COD+BOD=180°3x+7°+2x-19°+x°=180°6x=192°x=32°
Therefore,
AOC=3×32°+7=103°COD=2×32°-19=45° andBOD=32°

Question 4:

In the adjoining figure, x:y:z = 5:4:6. If XOY is a straight line, find the values of x, y and z.








Answer 4:

Let x=5a, y=4a and z=6a
XOY is a straight line. Therefore,

XOP+POQ+YOQ=180°5a+4a+6a=180°15a=180°a=12°
Therefore,

      x5×12°=60°      y4×12°=48°and z6×12°=72°

Question 5:

In the adjoining figure, what value of x will make AOB a straight line?







Answer 5:

AOB will be a straight line if
3x+20+4x-36=180°7x=196°x=28°
Hence, x = 28 will make AOB a straight line.

Question 6:

Two lines AB and CD intersect at O. If ∠AOC = 50°, find ∠AOD, ∠BOD and ∠BOC.






Answer 6:

We know that if two lines intersect then the vertically-opposite angles are equal.
Therefore, AOC=BOD=50°
Let AOD=BOC=x°
Also, we know that the sum of all angles around a point is 360°.
Therefore, 
AOC+AOD+BOD+BOC=360°50+x+50+x=360°2x=260°x=130°
Hence, AOD=BOC=130°
Therefore, AOD=130°, BOD=50° and BOC=130°.

Question 7:

In the adjoining figure, three coplanar lines AB, CD and EF intersect at a point O, forming angles as shown. Find the values of x, y, z and t.












Answer 7:

We know that if two lines intersect, then the vertically opposite angles are equal.
BOD=AOC=90°
Hence, t=90°
Also, 
DOF=COE=50°
Hence, z=50°
Since, AOB is a straight line, we have:
AOC+COE+BOE=180°90+50+y=180°140+y=180°y=40°
Also,
BOE=AOF=40°
Hence, x=40°
 x=40°, y=40°, z=50° and t=90°

Question 8:

In the adjoining figure, three coplanar lines AB, CD and EF intersect at a point O. Find the value of x. Also, find ∠AOD, ∠COE and ∠AOE.







Answer 8:

We know that if two lines intersect, then the vertically-opposite angles are equal.
DOF=COE=5x°AOD=BOC=2x° andAOE=BOF=3x°

Since, AOB is a straight line, we have:
AOE+COE+BOC=180°3x+5x+2x=180°10x=180°x=18°

Therefore,
AOD=2×18°=36°COE=5×18°=90°AOE=3×18°=54°

Question 9:

Two adjacent angles on a straight line are in the ratio 5 : 4. Find the measure of each of these angles.

Answer 9:

Let the two adjacent angles be 5x and 4x, respectively.
Then,
5x+4x=180°9x=180°x=20°
Hence, the two angles are 5×20°=100° and 4×20°=80°.

Question 10:

If two straight lines intersect in such a way that one of the angles formed measures 90°, show that each of the remaining angles measures 90°.

Answer 10:

We know that if two lines intersect, then the vertically-opposite angles are equal.

AOC=90°. Then, AOC=BOD=90°.
And let BOC=AOD=x
Also, we know that the sum of all angles around a point is 360°
AOC+BOD+AOD+BOC=360°90°+90°+x+x=360°2x=180°x=90°
Hence, BOC=AOD=90°
AOC=BOD=BOC=AOD=90°
Hence, the measure of each of the remaining angles is 90o.



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