ML AGGARWAL CLASS 7 Chapter 1 INTEGERS EXERCISE 1.4

 

 Exercise 1.4

Question 1


(i) $(-36) \div(-9)$

$\begin{aligned}=+(36 \div 9) &=+4 \\ &=4 \end{aligned}$


(ii) $150 \div(-25)$

$=-(150+25)$

$=-6$


(iii) $(-270) \div 27$

$=-(270+27)$

=-10


(iv) $(-59)+(59)$

$=-(59 \div 59)$

=-1


(v) $0 \div(-17)$

$=0$


(vi) $(-784) \div(-56)$

$=+(784 \div 56)$

$=+14$

$=14$



Question 2


(i) $13 \div[(-2)+1]$

$=13 \div[-2+1]$

$=13 \div[-1]$

$=-[13 \div 1]$

=-13 


(ii) $(-47) \div[(-45)+(-2)]$

$=(-47) \div[-45-2]$

$=(-47) \div(-47)$

$=+[47 \div 47]$

=1


(iii) $[(-6)+5] \div[(-2)+1]$

$=[-6+5] \div[-2+1]$

$=(-1) \div(-1)$

=1


(iv) $[(-48) \div(-6)] \div(-2)$

$=[+(48 \div 6)] \div(-2)$

$=[8] \div(-2)$

$=-[8+2]$

=-4 


Question 3


$(a+b) \div c$                                      

$=[(-225) \div 15] \div(-3)$                        

$=[-(225 \div 15)] \div(-3)$

$=(-15) \div(-3)$

$=+(15+3)$

$=5$


 $a \div(b+c)$

$=(-225) \div(15 \div(-3))$

$=(-225) \div(-(15 \div 3))$

$=(-225) \div(-5)$

$=+(225 \div 5)$

=45

$5 \neq 45$

Verified



Question 4

 
(i)
 $\begin{aligned} & a \div(b+c) \\=&(-10) \div(1+1) \\=&(-10) \div(2) \\=&-(10 \div 2) \\=&-5 \end{aligned}$

$(a \div b)+(a \div c)$

$=(-10+1)+(-10 \div 1)$

$\equiv-10+(-10)$

$=-10-10$

$=-20$

$-5 \neq-20$

$\therefore$ verified


(ii) 
$\begin{aligned} & a \div(b+c) \\=& 12\div(1+(-2)) \\=& 12 \div(1-2) \\=& 12+(-1) \\=&-(12 \div 1) \quad ; \\=&-12 \end{aligned}$

$(a \div b)+(a \div c)$
$=(12 \div 1)+(12 \div(-2))$
$=12+[-(12 \div 2)]$
=$12+[-6]$
=$12-6$
=6

$-12 \neq 6$

verified.



Question 5


We know $a \div a=1 \quad-a \div a=-1$

i) $239 \div 239=1$

ii) $(-85) \div 85=-1$

iii) $(-213) \div(-213)=1$

iv) $(-43) \div(-1)=43$

v) $(-84) \div(-21)=4$

vi) $(-66) \div 22=-3$


Question 6


$a \div b=-3$

$\frac{a}{b}=-3 \Rightarrow a=-3 b$

$b=1 ; a=-3 \times 1=-3$

$b=2 ; a=-3 \times 2=-6$

$b=3 ; a=-3 \times 3=-9$

$b=4: a=-3 \times 4=-12$

$b=5 ; a=-3 \times 5=-15$

∴ Five p;airs are $(-3,1)(-6,2)(-9,3)(-12, 4)(-15,5)$




Question 7


(i) Marks Scored for 14 Correct answer = $14 \times 3=42$

Sachin's Score = 24

∴ Marks obtained for incorrect answer $=-42+24$

=-18 

∴ The number of incorrect answer = $(-18) \div(-2)$

=9


(ii) Marks Scored for 9 correct answers $=9 \times 3$

$=27$
  
Nalini's Score = -7

Marks obtained for incorrect answers = $-7-27$

$-34$

Marks given for one incorrect answer = -2

∴ The number of incorrect answer = $(-34) \div(-2)$

$=3 4+2$

=17


Question 8


Elevator descends at a rate of $6 \mathrm{~m} / \mathrm{min}$.
Descend starts from 10m above ground level 
It has to reach the shaft 350m below ground level 

Total 360 m it has to reach

$\begin{aligned} \text { Time } &=\frac{\text { Distance }}{\text { speed }} \\ &=\frac{360}{6} \\ &=60 \mathrm{~min} \end{aligned}$

$\therefore$ Time $=1$ hour

$\therefore$ It will take 1hour to reach the shaft

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