Exercise 1.1
Question 1
(i) Ascending order is -18,-9,-4,0,3,8,12
(ii) Desending order is 12, 8, 3, 0, -4, -9, -18
(iii)From left -17,-14,-11,-3,-5,-3,1,4,7,9,11
Question 2
B is -6
D is -4
H is 0
J is 2
M is 5
O is 7
Question 3
Ascending order is -5,-4,0,4,7
(Daigram should be added)
Question 4
Rohit scores in five successive rounds were 15, -3, -7 , 12,8
Total score at end = Sum of all scores
=15+(-3)+(-7)+12+8
=15-3-3+20=25
∴ Rohit total score at end = 25
Question 5
Ruchi deposited on monday = Rs 4370
She withdrew on tuesday = Rs 2875
On tuesday , the money left = 4370 - 2875
=Rs 1495
Next day i.e on wednesday
She deposited = Rs 1550
Total money in bank = 1550+1495
=Rs 3045
∴ Balance on thusday =Balance on wednesday
=Rs 3045
Question 6
(Daigram should be added)
Final position from p is 28 - 37= -9
Question 7
Let the unfilled boxes be 1st row 2nd Box be p
3rd Box be Q
2nd row 3rd Box be R
3rd row Sequentially x, y , z
Given information all the sum of integers in each row colume and each digram is -6
i.e $\begin{aligned}-1+3+1 &=-6 \\ 2+x &=-6 \\ x &=-6-2 \\ x &=-8 \end{aligned}$
= - 8 + (-2)+Q=-6
= - 8 - 2+Q= -6
= -10 + Q= -6
Q= - 6+10 = 4
$\begin{aligned}-1+p+4 &=-6 \\ p+3 &=-6 \\ p &=-6-3 \\ &P= -9 \end{aligned}$
$\begin{aligned}-8+5+z &=-6 \\-3+z &=-6 \\ z &=-6+3 \\ z &=-3 \end{aligned}$
$\begin{array}{|c|c|c|}\hline-1 & P & Q \\\hline 3 & -2 & R \\\hline x & y & z \\\hline\end{array} \Rightarrow \begin{array}{|c|c|c|}\hline-1 & -9 & 4 \\\hline 3 & -2 & 7 \\\hline-8 & 5 & -3 \\\hline\end{array}$
Question 8
(i) $|-13|-|9|$
We know $|-a|=a$
$=13-9=4$
(ii) $|13-5|-|-9|$
$=|8|-|-9|$
$=8-9$
$=-1$
(iii) $|3 5-21|-| 8-3 \mid$
$=|14|-|5|$
$=14-5$
$=9$
Question 9
Ascending order is -102,-51,-39,-6,-5,0,7,35
Question 10
Desending order is 4208 , 139, 0 ,-31, -97,-203
Question 11
(i) True ,it lies left to 0
(ii) False, it will have predecessor and successor
(iii) True
(iv)True
Question 12
(i) $(-11)+(-7) ;(-11)-(-7)$
$=-11-7 \quad ;(-11+7)$
$=-18 \quad ;-4$
As $-18<-4$
(ii)
$\begin{aligned} 23-41+11 & ; 23-41-11 \\=34-41 & ; 23-52 \\=-7 & ;-29 \\ \therefore-7 &>-29 \end{aligned}$
(iii) $40-(-39)+(-5)$
$=40+39-5$
$=79-5$
$=74$
=$40+(-39)-(-5)$
=$40-39+5$
=$1+5$
=6
∴ 74>6
(iv)
$\begin{aligned}(-3)+13-(15) &: 25-(-2)+(-33) \\-3+13-15 & ; 25+2-33 \\ 13-18 & ; 27-33 \\-5 & ;-6 . \\-5 &>-6 \end{aligned}$
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