ML AGGARWAL CLASS 7 Chapter 1 INTEGERS EXERCISE 1.1

 Exercise 1.1


Question 1


(i) Ascending order is -18,-9,-4,0,3,8,12

(ii) Desending order is 12, 8, 3, 0, -4, -9, -18

(iii)From left -17,-14,-11,-3,-5,-3,1,4,7,9,11


Question 2

B is -6

D is -4

H is 0

J is 2

M is 5

O is 7


Question 3


Ascending order is -5,-4,0,4,7

(Daigram should be added)



Question 4


Rohit scores in five successive rounds were 15, -3, -7 , 12,8

Total score at end = Sum of all scores 

=15+(-3)+(-7)+12+8

=15-3-3+20=25

∴ Rohit total score at end = 25



Question 5


Ruchi deposited on monday = Rs 4370 

She withdrew on tuesday = Rs 2875

On tuesday , the money left = 4370 - 2875

=Rs 1495

Next day i.e on wednesday 

She deposited = Rs 1550

Total money in bank = 1550+1495

=Rs 3045

∴ Balance on thusday =Balance on wednesday 

=Rs 3045 


Question 6


(Daigram should be added)

Final position from p is 28 - 37= -9



Question 7


Let the unfilled boxes be 1st row 2nd Box be p

3rd Box be Q 

2nd row 3rd Box be R 

3rd row Sequentially x, y , z

Given information all the sum of integers in each row colume and each digram is -6

i.e $\begin{aligned}-1+3+1 &=-6 \\ 2+x &=-6 \\ x &=-6-2 \\ x &=-8 \end{aligned}$ 

= - 8 + (-2)+Q=-6

= - 8 - 2+Q= -6

= -10 + Q= -6

Q= - 6+10 = 4


$\begin{aligned}-1+p+4 &=-6 \\ p+3 &=-6 \\ p &=-6-3 \\ &P= -9 \end{aligned}$


$\begin{aligned}-8+5+z &=-6 \\-3+z &=-6 \\ z &=-6+3 \\ z &=-3 \end{aligned}$

$\begin{array}{|c|c|c|}\hline-1 & P & Q \\\hline 3 & -2 & R \\\hline x & y & z \\\hline\end{array} \Rightarrow \begin{array}{|c|c|c|}\hline-1 & -9 & 4 \\\hline 3 & -2 & 7 \\\hline-8 & 5 & -3 \\\hline\end{array}$



Question 8


(i) $|-13|-|9|$

We know $|-a|=a$

$=13-9=4$

(ii) $|13-5|-|-9|$

$=|8|-|-9|$

$=8-9$

$=-1$

(iii) $|3 5-21|-| 8-3 \mid$

$=|14|-|5|$

$=14-5$

$=9$


Question 9


Ascending order is -102,-51,-39,-6,-5,0,7,35

Question 10

Desending order is 4208 , 139, 0 ,-31, -97,-203



Question 11

(i) True ,it lies left to 0 

(ii) False, it will have predecessor and successor 

(iii) True 

(iv)True 


Question 12


(i) $(-11)+(-7) ;(-11)-(-7)$

$=-11-7 \quad ;(-11+7)$

$=-18 \quad ;-4$

As $-18<-4$


(ii)
$\begin{aligned} 23-41+11 & ; 23-41-11 \\=34-41 & ; 23-52 \\=-7 & ;-29 \\ \therefore-7 &>-29 \end{aligned}$


(iii) $40-(-39)+(-5)$

$=40+39-5$

$=79-5$

$=74$


=$40+(-39)-(-5)$

=$40-39+5$

=$1+5$

=6

∴ 74>6


(iv) 
$\begin{aligned}(-3)+13-(15) &: 25-(-2)+(-33) \\-3+13-15 & ; 25+2-33 \\ 13-18 & ; 27-33 \\-5 & ;-6 . \\-5 &>-6 \end{aligned}$

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