Exercise 4.1
Q1 | Ex-4.1 | Class 9 | Factorisation | ML Aggarwal Maths | Chapter 4 | myhelper
Question 1
(i) 8xy3+12x2y2
Sol :
⇒4xy2(2y+3x)
∴H.C.F of 8xy3 and 12x2y2 is 4xy2
(ii) 15ax3-9ax2
Sol :
∴H.C.F of 15ax3 and 9ax2 is 3ax2
⇒3ax2(5x-3)
Q2 | Ex-4.1 | Class 9 | Factorisation | ML Aggarwal Maths | Chapter 4 | myhelper
Question 2
(i) 21py2-56py
Sol :
∴H.C.F of 21py2 and 56py is 7py
⇒7py(3y-8)
(ii) 4x3-6x2
Sol :
∴H.C.F of 4x3 and 6x2 is 2x2
⇒2x2(2x-3)
Q3 | Ex-4.1 | Class 9 | Factorisation | ML Aggarwal Maths | Chapter 4 | myhelper
Question 3
(i) 2πr2-4πr
Sol :
H.C.F of 2πr2 and 4πr is 2πr
∴2πr(r-2)
(ii) 18m+16n
Sol :
H.C.F of 18m and 16n is 2
⇒2(9m+8n)
Q4 | Ex-4.1 | Class 9 | Factorisation | ML Aggarwal Maths | Chapter 4 | myhelper
Question 4
(i) 25abc2-15a2b2c
Sol :
∴H.C.F of 25abc2 and 15a2b2c is 5abc
∴⇒5abc(5c-3ab)
(ii) 28p2q2r-42pq2r2
Sol :
∴H.C.F of 28p2q2r and 42pq2r2 is 14pq2r
⇒∴14pq2r(2p-3r)
Q5 | Ex-4.1 | Class 9 | Factorisation | ML Aggarwal Maths | Chapter 4 | myhelper
Question 5
(i) 8x3-6x2+10x
Sol :
∴H.C.F of 8x3 ,6x2 ,10x is 2x
∴⇒2x(4x2-3x+5)
(ii) 14mn+22m-62p
Sol :
H.C.F of 14mn , 22m and 62p are 2
∴⇒2(7mn+11m-31p)
Q6 | Ex-4.1 | Class 9 | Factorisation | ML Aggarwal Maths | Chapter 4 | myhelper
Question 6
(i) 18p2q2-24pq2+30p2q
Sol :
H.C.F of 18p2q2,24pq2 and 30p2q is 6pq
⇒6pq(3pq-4q+5p)
(ii) 27a3b3-18a2b3+75a3b2
Sol :
H.C.F of 27a3b3 ,18a2b2 and 75aa3b2 is 3a2b2
⇒3a2b2(9a-6b+25a)
Q7 | Ex-4.1 | Class 9 | Factorisation | ML Aggarwal Maths | Chapter 4 | myhelper
Question 7
(i) 15a(2p-3q)-10b(2p-3q)
Sol :
H.C.F of 15a(2p-3q) and 10b(2p-3q) is 5(2p-3q)
⇒5(2p-3q)[3a-2b]
(ii) 3a(x2+y2)+6b(x2+y2)
Sol :
H.C.F of 3a(x2+y2) and 6b(x2+y2) is 3(x2+y2)
⇒3(x2+y2)(a+2b)
Q8 | Ex-4.1 | Class 9 | Factorisation | ML Aggarwal Maths | Chapter 4 | myhelper
Question 8
(i) 6(x+2y)3+8(x+2y)2
Sol :
H.C.F of 6(x+2y)3 and 8(x+2y)2 is 2(x+2y)2
⇒2(x+2y)2[3(x+2y)+4]
(ii) 14(a-3b)3-21p(a-3b)
Sol :
H.C.F of 14(a-3b)3 and 21p(a-3b) is 7(a-3b)
⇒7(a-3b)[2(a-3b)2-3p]
Q9 | Ex-4.1 | Class 9 | Factorisation | ML Aggarwal Maths | Chapter 4 | myhelper
Question 9
(i) 10a(2p+q)3-15b(2p+q)2+35(2p+q)
Sol :
H.C.F is 5(2p+q)
⇒5(2p+q)[2a(2p+q)2-3b(2p+q)+7]
(ii) x(x2+y2-z2)+y(-x2-y2+z2)-z(x2+y2-z2)
Sol :
H.C.F is x2+y2-z2
⇒(x2+y2-z2)[x-y-z]
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