S.chand publication New Learning Composite mathematics solution of class 8 Chapter 8 Percentage and Its Application Exercise 8D

 Exercise 8D


Q1 | Ex-8D | Class 8 | S.Chand | New Learning Composite maths |Percentage and its application | myhelper

Question 1

Find the simple interest and the amount of simple interest of

(a) Rs. 350 for 3 years at 6%

Sol :

I=PRT100=350×6×3100

=63


(b) Rs. 765 for 2 1 by 2 years at 5 1 by 3 percent

Sol :

P=765

T=212=52y

R=513=163%

I=?

I=PRT100=765×163×52100

=765×16×5100×3×2

=102

∴Total amount of simple interest=102+765

=867


(c) Rs. 475 for 2 years 4 months at 4 and 1 by 2 percent.

Sol :

P=475

R=412=92%

T=2year 4month

=2+412

=2+13=73



I=PRT100=475×9×7100×2×3


∴Amount simple interest

=48.875+475

=524.875


(d) Rs. 1900 for 20 months at 6%

Sol :

P=1900 , R=6%

I=PRT100=1900×6×5100×3

=190


∴Total I=190+1900=2090


(e) Rs. 7300 for April 5 to June 24 at 5%

Sol :

P=7300 , R=5%

T=5th april to 2 years =80365years


I=PRT100=7300×5×80100×365

=80


∴Total I=7300+80

=7380



Q2 | Ex-8D | Class 8 | S.Chand | New Learning Composite maths |Percentage and its application | myhelper

Question 2

Find the rate per cent p.a. when Rs. 800 yields Rs. 80 interest in 2 years.

Sol :

I=PRT100

or R=100IPT=100×80800×2

=5%



Q3 | Ex-8D | Class 8 | S.Chand | New Learning Composite maths |Percentage and its application | myhelper

Question 3

In what times Rs. 600 will yield Rs. 48 interest at 4% p.a.?

Sol :

P=600,  I=48 , R=4%

T=I100PR=48×100600×4

=2 year



Q4 | Ex-8D | Class 8 | S.Chand | New Learning Composite maths |Percentage and its application | myhelper

Question 4

Find what sum of money will yield Rs. 231 interest in 3 years at 7% p.a.

Sol :

I=231 , T=3 year, R=7%

I=PRT100

P=I×100RT

P=231×1003×7

=1100

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