Exercise 8D
Question 1
Find the simple interest and the amount of simple interest of
(a) Rs. 350 for 3 years at 6%
Sol :
I=PRT100=350×6×3100
=63
(b) Rs. 765 for 2 1 by 2 years at 5 1 by 3 percent
Sol :
P=765
T=212=52y
R=513=163%
I=?
I=PRT100=765×163×52100
=765×16×5100×3×2
=102
∴Total amount of simple interest=102+765
=867
(c) Rs. 475 for 2 years 4 months at 4 and 1 by 2 percent.
Sol :
P=475
R=412=92%
T=2year 4month
=2+412
=2+13=73
I=PRT100=475×9×7100×2×3
∴Amount simple interest
=48.875+475
=524.875
(d) Rs. 1900 for 20 months at 6%
Sol :
P=1900 , R=6%
I=PRT100=1900×6×5100×3
=190
∴Total I=190+1900=2090
(e) Rs. 7300 for April 5 to June 24 at 5%
Sol :
P=7300 , R=5%
T=5th april to 2 years =80365years
I=PRT100=7300×5×80100×365
=80
∴Total I=7300+80
=7380
Question 2
Find the rate per cent p.a. when Rs. 800 yields Rs. 80 interest in 2 years.
Sol :
I=PRT100
or R=100IPT=100×80800×2
=5%
Question 3
In what times Rs. 600 will yield Rs. 48 interest at 4% p.a.?
Sol :
P=600, I=48 , R=4%
T=I100PR=48×100600×4
=2 year
Question 4
Find what sum of money will yield Rs. 231 interest in 3 years at 7% p.a.
Sol :
I=231 , T=3 year, R=7%
⇒I=PRT100
P=I×100RT
P=231×1003×7
=1100
This is very good
ReplyDelete