S.chand publication New Learning Composite mathematics solution of class 8 Chapter 5 Algebraic Expressions Exercise 5E

 Exercise 5E

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Q1 | Ex-5E | Class 8 |Algebraic Expressions | S.chand  | New Learning Composite mathematics | Chapter 5  | myhelper

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Question 1

Simplify:

(a) $\frac{9x^7}{3x^5}$
Sol :

=3x^7-5=3x²

(b) $\frac{-20y^{12}}{4y^8}$
Sol :

=-5y^12-8=-5y⁴

(c) $\frac{-15a^7}{-3a^{15}}$

Sol :

=5a^7-15=5a^-8

$=\frac{5}{a^8}$

(d) $\frac{18x^4y^2}{9x^3y}$
Sol :

=2xy

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Q2 | Ex-5E | Class 8 |Algebraic Expressions | S.chand  | New Learning Composite mathematics | Chapter 5  | myhelper

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Question 2

(a) $\frac{-35x^8y^9}{-7x^3y^2}$
Sol :

=5x⁵y⁷

(b) $\frac{48a^2b^2c^4}{-12abc^3}$

Sol :
=-4abc

(c) $\frac{10x^{20}y^7z^4}{0.1x^{16}y^3z^9}$
Sol :

=100x⁴y⁴z^-5

$=\frac{100x^4y^4}{z^5}$ 

(d) $\frac{0.6a^4b^3c^2}{0.3ab^5c^7}$

Sol :

=2a³b^-2c^-5

$=\frac{2a^3}{b^2c^5}$

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Q3 | Ex-5E | Class 8 |Algebraic Expressions | S.chand  | New Learning Composite mathematics | Chapter 5  | myhelper

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Question 3

(a) $\frac{(3a^3b)(5ab^3)}{(5ab)(6ab^7)}$
Sol :

$=\frac{3\times a^3 \times b\times 5\times a\times b^3}{5\times a\times b\times 6\times a\times b^7}$

$=\frac{a^2}{2b^4}$

(b) $\frac{4ab(-7a^3b^7)}{-14a^2b^2}$

Sol :

$=4\times a\times b \times (-7)\times a^3 \times b^7$
=2a²b⁶

(c) $\frac{(5a^2b)^2(-100b^3)}{(5^2b)^2}$

Sol :

$=\frac{5^2 \times a^4 \times b^2 \times (-100)\times b^3}{5^4 b^2}$

=-4a⁴b³

(d) $\frac{(-2x^2y)^3}{(6xy^2)^2}$

Sol :

$=\frac{-8x^6y^3}{36x^2y^4}=\frac{-2x^4}{9y}$

(e) $\frac{(3x^2)^3(3y)}{(3x)^3(3x)^2}$

Sol :

$=\frac{3\times 3\times 3\times 3\times x^6\times y}{3\times 3\times 3\times 3^2\times x^2\times x^3 }=\frac{xy}{3}$

(f) $\frac{(-2pq^2)^8}{(4p^2q)^4}$
Sol :

$=\frac{-2^8 \times p^8 \times q^{16}}{2^8 \times p^8 \times q^4}$

=q¹²