S.chand publication New Learning Composite mathematics solution of class 8 Chapter 13 Data Handling Exercise 13C

 Exercise 13C

Question 1

Sol :

Total number of students=60+12+36+72=180

Angle of students transport by bus$=\frac{60}{180}\times 360$=120°

Angle of students transport by car$=\frac{12}{180}\times 360$=24°

Angle of students transport by scotter$=\frac{36}{180}\times 360$=72°

Angle of students transport by wallk$=\frac{72}{180}\times 360$=144°

∴Angles are 120° , 24°, 72° , 144°

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Question 2

Sol :

Total students=20+15+10+9+6=60

Angle of students for football$=\frac{20}{60}\times 360$

=120°

Angle of students for basketball$=\frac{15}{60}\times 360$

=90°

Angle of students for hockey$=\frac{10}{60}\times 360$

=60°

Angle of students for batminton$=\frac{9}{60}\times 360$

=54°

Angle of students for boxing$=\frac{6}{60}\times 360$

=36°

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Question 3

Sol :

Total percentage=(50+15+25+10)%=100%

Entertainment in angle$=\frac{50}{100}\times 360$

=180°

News in angle$=\frac{15}{100}\times 360$

=52°

Sports in angle $=\frac{25}{100}\times 360$

=90°

Others in angle$=\frac{10}{100}\times 360$

=36°

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Question 4

Sol :

Let, the angle of the sector representing in the population of the city D = x°

We know that,

⇒120°+96°+60°+x°=360°

Or, x=360°–270°=84°

∴ A sector of 120° presents 100 lakh population

∴ A sector of 1° presents $\frac{100}{120}=\frac{5}{6}$ population.

Similarly, D sector 940 presents $=\frac{5}{6}\times 84$= 70°

Question 5

Sol :

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(a)

We know that-

⇒2x+5x+81+55=360°

⇒7x+136°=360°

⇒7x=360°-136°=224°

$x=\frac{224}{7}$=32° (proved)

(b)

The percentage of the se group$=\frac{81}{360}\times 100$

$=\frac{45}{2}=22\frac{1}{2}$%

(c)

Number of students who choose mathematics=48 

Total angle of section without mathematics=55°+81°+(2×32)°

=55°+81°+64°=200°

Total angle of section with mathematics=(5×32)=160°

∴160° represents 48 pupils

∴1° represents $=\frac{48}{160}$

∴200° represents $=\frac{48}{160}\times 200$=60 pupils

∴Number of students without math=60

∴Total group of students=60+48=108 pupils

Question 6

Sol :

<Figure to be added>

∵360° represents 800 students 

1° represents $\frac{800}{360}$ students 

(a) Students come in public bus $=\frac{800}{360}\times 54$

=120 pupils

(b) The angle of section of the students who are come on foot

=360°-(216°+18°+54°)

=360°-288°

=72°

Total angle who do not use institute bus $=\frac{800}{360}\times 144$

=320°

(c) The students angle who come on foot=72°

∴Number of student who come on foot$=\frac{800}{360}\times 72$

=162 pupils