S.chand publication New Learning Composite mathematics solution of class 8 Chapter 12 Mensuration Exercise 12E

 Exercise 12E


Q1 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 1

Find the volume of each of the following cuboids

(a)







Volume=l×b×h

=6×4×5=120cm3


(b)







Volume=l×b×h

=7×7×10=490cm3


(c)







Volume=l×b×h

=11×8×2=176cm3


(d)









Volume=l×b×h

=3×2×9=54cm3



Q2 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 2

Find the volume of each of the following cuboids

(a) Length =12 cm, width =7 cm, height =8 cm

Sol :

(a) 

Length=12cm, Width=7cm , Height=8cm

Volume=l×b×h=12×7×8=672cm3


(b) Length =16 cm, width =16 cm, height =10 cm

Sol :

(b)

Length=16cm, Width=16cm , Height=10cm

Volume=l×b×h=16×16×10=2560cm3


(c) Length =3.5 m, width =2.8 m, height =2 m

Sol :

(c)

Length=3.5m, Width=2.8m , Height=2m

Volume=l×b×h=3.5×2.8×2=19.6 m3



Q3 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 3

Find the volume of each cube of side length:

(a) 5 cm

(b) 8 cm

(c) 0.3 m

(d) 50 mm

(e) 1.2 m

Sol :

(a) volume=l3=53=125 cm3
(b) volume=l3=83=612 cm3
(c) volume=l3=(0.3)3=0.027 m3
(d) volume=l3=(50)3=125000 mm3
(e) volume=l3=(1.2)3=1.728 m3



Q4 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 4

A cuboidal water tank is 7 m long, 5 m width and 4 m deep. How many litres of water can it hold?

Sol :

Tank can hold water= l×b×h

=7×5×4=140 m3

∵1m3=1000l

multiplying both side by 140

(140×1) m3=(140×1000) l



Q5 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 5

A cuboidal tank is 12 m long and 8 m wide. What should be its height so that it may hold $960 \mathrm{~m}^{3}$ of water?

Sol :

Water it can hold=960m3

Length of tank=l=12m

Width of tank=8m


ATQ,

l×w×h=960

$h=\frac{960}{l\times w}=\frac{960}{12\times 8}$

=10 m



Q6 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 6

A solid cube of side 12 cm is cut into eight cubes of equal volume. Calculate the size of the new cube.

Sol :

Large cube volume=l3=(12)3

=1728 cm3

∴Large cube is cut into 8 cube

∴Small cube volume$=\frac{1728}{8}$

=216 cm3



Q7 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 7

A cube of side length 8 cm is immersed completely in a rectangular vessel containing water. If the base is 16 cm long and  10 cm wide, then, find the rise in water level in the vessel.

Sol :

Volume of cube=83

=512cm3

The water level rise due to immerse of cube.

∴Rise in water level= h cm

The volume of water rise is equal to volume of the cube.

∴Volume of water rise=16×10×h=512

$h=\frac{512}{16\times 10}$

=3.2cm

∴Water level rise=3.2cm



Q8 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 8

A godown is in the form of a cuboid measuring 40 m by 30 m by 20 m. How many cuboidal boxes of volume $1.2 \mathrm{~m}^{3}$ each can be stored in the godown?

Sol :

Volume of godown=40×30×30=24000m3

1.2mof volume need=1 cuboidal box

∴24000mof volume needed$=\frac{24000}{1.2}$

$=\frac{240000}{12}=20000$

∴Number of cuboidal box=20000



Q9 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 9

A machine for making ice bricks freezes 5.76 litres of water into ice cubes measuring 4 cm by 3 cm by 2 cm. How many ice bricks will be made?

Sol :

We know that:-

1litre=1000cm3

∴5.76litre=5.76×1000=5760cm3

∴Volume of Ice cubes=4×3×2=24cm3

∴Ice bricks will be made$=\frac{5760}{24}=240$



Q10 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 10

A storage tank at a petrol station is a cuboid 4 m long , 3 m wide and 2 m deep. In one day if the station sells 7200 litres of petrol from the tank, what is the fall in the level of the petrol in the tank?

Sol :

Volume of petrol storage tank=4×3×2=24m3

We know that:-

1Litre=0.001m3

∴7200litre=7200×0.001$=\frac{7200}{1000}$=7.2m3

Let , the fall level=x m

∴ATQ,

4×3×2=7.2

12x=7.2

$x=\frac{7.2}{12}$=0.6m

=60cm or 0.6 m



Q11 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 11

The platform at the base of a statue is to be built to a height of 1.5 m on a square base measuring 2 m by 2 m. It is to be constructed from bricks of dimensions 25 cm, 15 cm and 10 cm. How many bricks will be required to build the base of the statue?

Sol :

∵1m=100 cm

∴2m=200 cm and 1.5m=150 cm

Volume of required area=200×200×150
=6000000cm3

Single brick dimension=25×15×10cm

=3750cm3

∴Brick needed$=\frac{6000000}{3750}$

=1600



Q12 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 12

On a certain day 8 cm of rain fell. Calculate the volume of water that fell on 1.8 ha of land.

Sol :

∴Depth of water on the land=8cm or 0.08m

We know that:-

1h=10000m2

1.8h=10000×1.8=18000m2

∴Volume of water=0.08×18000=1440m3



Q13 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 13

A covered wooden box has the inner measure as 115 cm, 75 cm and 35 cm and the thickness of wood is 2.5 cm. Find the volume of the wood.

Sol :

Inner volume=115×75×35cm
=301875cm3

∴External length=115+(2.5×2)=120cm
External Breadth=75+(2.5×2)=80cm
External Height=35+(2.5×2)=40cm

∴External volume=120×80×40
=384000cm3

∴Only wooden volume=384000-301875
=82125cm3



Q14 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 14

Each side of a cube is decreased by 25% . Find the ratio of the volume of the original cube and the resulting cube.

Sol :

Let original cube's side=100unit
∴Original cube volume=(100)3unit3

Decreasing 25% of side
∴New cube's side$=100-\left(100\times \frac{25}{100}\right)$
=100-25=75unit

∴New cube volume=(75)3

∴Original cube's volume : New cube's volume
=(100): (75)
$=\frac{100\times 100 \times 100}{75 \times 75 \times 75}=\frac{4^3}{3^3}$
$=\frac{64}{27}$

=64 : 27



Q15 | Ex-12E |Class 8 |Mensuration | S.Chand | New Learning | Composite mathematics | myhelper

Question 15

100 men took a dip in a pond 50 m long and 18 m wide. If the average displacement of water by a man was 3.6m3 , then calculate the rise in the water level.

Sol :

Each man displacement of water=3.6m3

∴100 man displacement of water=3.6×100=360m3

Rise in water level in pond is same as height of volume of cuboid

ATQ ,
50×18×h=360
$h=\frac{360}{50\times 8}$
=0.9m=90cm

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