S.chand publication New Learning Composite mathematics solution of class 8 Chapter 11 Representing 3D Shapes in 2D Exercise 11A

 Exercise 11A

Question 1

Sol :

(a)

h=6cm , a=8cm ,b=11cm

Area =12×h(a+b)

=12×6(8+11)

=12×6×19

=57cm2


(b)

h=10cm, a=12cm, b=9cm

Area=12h(a+b)

=12×10(12+9)

=5×21=105cm2


(c)

h=4cm, a=3cm, b=5cm

Area=12h(a+b)=12×4(3+5)

=2×8=16cm2


Question 2

Sol :

Area=80cm2

a=9cm

b=7cm

∴We know

Area=12h(a+b)

80=12h(9+7)

h=80×216=10 cm


Question 3

Sol :

a+b=25cm

Area=150cm2

We know that-

Area=12h(a+b)

h=area×225=150×25

=12cm


Question 4

Sol :

Area=126cm2

h=6cm

a+b=?

We know that-

Area=12h(a+b)

a+b=126×26

a+b=42


Question 7

Sol :

Let , a=x

b=x-20

h=22 m

Area=450m2

We know that

12×h(a+b)=450

12×15(x+x20)=450

2x20=450×215

2x=60+20=80

x=80240

∴a=40m

b=40-20=20m


Question 8

Sol :

Let , common factor be x

a=7x , b=9x

Area=960cm2

h=15cm

According to question

Area=12h(a+b)

960=12×15(7x+9x)

16x=960×215

x=64×216=8


∴a=7×8=56cm

b=9×8=72cm


Question 9

Sol :

a=10cm =AB

b=20cm=CD

AD=BC=13cm

AD||BQ  ∴AD=BQ=13cm

AB||DB  ∴AB=DQ=15cm

∴QC=DC-DQ=20-10=10cm


∵BO bisects QC

∴QO=OC=102=5cm

∴h2=BO2=BC2-OC2

=132-52

=169-25=144


h=√144=12

A=12h(a+b)

=12×12(10+20)

=6×30=180cm2


Question 10

Sol :

AB=15cm

DC=31cm

AD=BC=17cm

AD||BE  ∴AD=BE=17cm

AD=BE=17cm

∴EC=DC-DE=31-15=16cm

∴OC=EO=162=8cm


∴ΔBOC-

BO2=BC2-OC2

=172-82

=289-64=225


BO=√225=15

∴BO=h=15cm


Area=12h(a+b)

=12×15(31+15)

=12×15×46

=343cm2


Question 11

Sol :

h=16m

a=20m

b=25m

A=12×h(a+b)

=12×16(20+25)

=8×45=360m2

∴Area of floor=360m2

Rate=40 per m2

∴Cost=360×40=14400

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