Exercise 8B
Question 1
Find.
(a) 25% of 32
Sol :
$\frac{25}{100}\times 32$
=8
(b) $16\frac{1}{3}%$ of 390
Sol :
$=\frac{49}{300}\times 390$
=63.7
(c) 50% of 29
Sol :
$=\frac{50}{100}\times 29$
=14.5
(d) $33\frac{1}{3}%$ of 150
Sol :
$=\frac{100}{300}\times 150$
=50
(e) 20% of 775
Sol :
$=\frac{20}{100}\times 775$
=155
(f) 15% of 3000
Sol :
$=\frac{15}{100}\times 3000$
=450
(g) 28% of 1225
Sol :
$=\frac{28}{100}\times 1225$
=343
(h) 18% of 2650
Sol :
$=\frac{18}{100}\times 2650$
=477
Question 2
(a) 10% of Rs. 775
Sol :
$=\frac{10}{100}\times 775$
=77.5
Ans : 77.5 Rs
(b) 15% of 800 kg
Sol :
$=\frac{15}{100}\times 800$
=120
Ans : 120 kg
(c) 45% of 180 L
Sol :
$=\frac{45}{100}\times 180$
=81 L
(d) 37% of Rs. 680
Sol :
$=\frac{37}{100}\times 680$
=251.6 Rs
(e) 120% of Rs. 65
Sol :
$=\frac{120}{100}\times 65$
=78 Rs
(f) $16\frac{2}{3}$% of 480 m
Sol :
$=\frac{500}{300}\times 480$
=80m
(g) 36% of 1.5 km = ____ m
Sol :
$=\frac{36}{100}\times 1500$
=540m
(h) $27\frac{1}{2}$% of 8 m = ____ cm
Sol :
$=\frac{55}{200}\times 800$
=200 cm
(i) $66\frac{2}{3}$% of 2 days = ____ h.
Sol :
$=\frac{200}{300}\times 48$ [2 days=48h]
=32 h
Question 3
A certain can of ice tea contains 4% of the recommended daily allowance of sodium. The recommended daily allowance is 2500 miligrams. How many miligrams of sodium are in the can of iced tea?
Sol :
∴Quantity of sodium are in the iced tea
$=\left(\frac{4}{100}\times 2500\right)$mg
=100
Question 4
27% of a fertiliser is superphosphate. How much superphosphate (in kg) is in 2 tonnes of the mixture?
Sol :
2 tonnes=2000 kg
∴Quantity of superphosphate$=\left(\frac{27}{100}\times 2000\right)$kg
Question 5
In a referendum, 68% of the 85,800 voters voted YES and the rest voted No. How many voted NO?
Sol :
Percentage of voter voted =100-68=32
∴Number of voters voted $=\frac{32}{100}\times 85800$
=27456
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