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S.chand publication New Learning Composite mathematics solution of class 7 Chapter 5 Algebraic Expression Exercise 5B

 Exercise 5B

Question 1

Add the following monomials.

(a) 5a, 9a

Sol : 14a


(b) 7x2, 3x2, x2

Sol : 11x2


(c) 2m2n, 6m2n, -5m2n

Sol : 3m2n


Question 2

Simplify:

(a) – xy2 – xy2 – xy2

Sol : =3xy2


(b) abc – abc +  abc

Sol : =abc


(c) 12xy + 3xy – 4xy

Sol : =11xy


(d) ab – 7ab + 10ab

Sol : =4ab


(e) – 3 – 2m – 4 + 7m

Sol : =-7+5m


Question 3

 Arrange in columns (vertical form) and add.

(a) 3a + 7b, 10a + b

Sol :

3a+7b10a+b13a+8b


(b) 8x + 5, 3x + 10

Sol :

8x+53x+1011x+15


(c) 2xy – yz, 5xy + 7yz

Sol :

2xyyz5xy+7yz7xy+6yz


(d) 7m2 + 9n2 , -4m2 – 2n2

Sol :

7m2+9n24m22m23m2+7n2


(e) 11x – 6y, 4x + 5y, 7x – 2y

Sol :

11x6y4x+5y7x2y22x3y


(f) 2x2 + 6x – 9, -5x2 + 7x – 1, 6x2 + 13x + 21

Sol :

2x2+6x95x2+7x16x2+13x+213x2+26x+11


(g) 5a2 + 6ab + 7b2, 6a2 – 2ab + 3b2, -4a2 – ab – 2b2

Sol :

5a2+6ab+7b26a22ab+3b24a2ab2b27a2+3ab+7b2


Question 4

Add the following without writing in columns (horizontally).

(a) 2a – 4b + 3c, -a + 7b – c

Sol : a+3b+2c


(b) 4m – 5n + 3p, -3m + 3n – 2p

Sol : m-2n+p


(c) 3ac +5b2, -ac + b2

Sol : 2ab+6b2


(d) 4a – b – c + 1, 2a + 4b + 4c – 8

Sol : 6a+3b+3c-7


(e) 5x2 + 8x – 4, 3x2 – 4x + 11

Sol : 8x2+4x+7


(f) 7m + 8n – 3mn, 9n + 7mn – 3m

Sol : 4m+17n+4mn


Question 5

Simplify:

(a) 14x2 – 2xy + y+ 5xy – 2y2 + 5 + x2 + 3y2 + 7

Sol : 15x2+3xy+2y2+12


(b) 7 – y3 + y + 9y2 + 2y3 + 6 + y2 + 5y – 19y + 3y3 – 2y2 + 15

Sol : 7–y3+y+9y2+2y3+6+y2+5y-19y+3y3-2y2+15

=28+4y3-13y+8y2


(c) 2ab – 4a + 3b – 7 + 6a – 11 – 8b + 3ab + 5 – 2ab + a – 4b

Sol :

=3ab+3a-9b-13

1 comment:

  1. Please send the solution not only answer because answers is also in books..

    ReplyDelete

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