S.chand publication New Learning Composite mathematics solution of class 7 Chapter 2 Fractions and Decimals Exercise 2A

Exercise 2A


Q1 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 1

Find the value of

(a) 15 of 1 hour 10 minutes

Sol :

1 h10 m={(1×60)+10}m=70 m15 of 70=15×70 m=14 m


(b) 15 of a non-leap year

Sol :

15 of 365days=(15×365)days=73



Q2 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 2

Express 12 as quarters, sixths, eighths, 12 ths, 16 ths and 24 ths.

Sol :

Quarters =12×22=24

Sixths =12×33=36

Eights =12×44=48

12 ths =12×66=612

16 ths =12×88=816

24 ths =12×1212=1224



Q3 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 3

Express 38 as fraction with

(a) numerator 15

(b) denominator 72

Sol :

(a) 38×55=1540
(b) 38×99=2772



Q4 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 4

Reduce each of the following fractions to its lowest terms.

(a) 1848

(b) 105120

(c) 210315

Sol :

(a) =18÷248÷2=9÷324÷3=38

(b) =105÷5120÷5=21÷324÷3=78

(c) =210÷5315÷5=42÷363÷3=14÷721÷7=23



Q5 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 5

Express each of the following mixed number as improper fraction


(a) 9710

=(9×10)+710

=9710


(b) 31522

=(3×22)+1522

=8122


(c) 181130

=(18×30)+1130

=55130



Q6 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 6

Express each of the following as mixed number

(a) 195=345

(b) 7724=3524

(c) 65950=13950



Q7 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 7

In each of the following write down the largest value and smallest value

(a) 211,811,511,911

Sol :

Largest value=911

Smallest value=211


(b) 23,27,25,29

Sol :

LCM of 3,7,5,9=315

2×1053×105=210315

2×457×45=90315

2×635×63=126315

2×359×35=70315

Largest value =23 

Smallest value =29


(c) 916,35,1120,2340

Sol :

LCM of 16,5,20,40 is 80

9×516×5=4580

3×165×16=4880

11×420×4=4480

23×240×2=4680

Largest value =35

Smallest value =1120


(d)  56,1315,2330,1418

Sol :

LCM of 6, 15, 30, 18 is 90

5×156×15=7590

13×615×6=7890

23×330×3=6990

14×518×5=7090

 Largest  value =1315 Smallest value=2330



Q8 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 8

Insert <  = or >

(a) 49512

Sol :

LCM of 9, 12 is 36

4×49×4=1636

5×312×3=1536

49>512


(b) 7241136

Sol :

LCM of 24,36 is 72

7×324×3=217211×236×2=2272

724<1136


(c) 451215

Sol :

LCM of 5, 15 is 15

4×35×3=1215

12×115×1=1215

45=1215



Q9 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 9

Arrange in descending order

(a) 310,25,13

Sol :

(a) LCM of 10, 5, 3 is 30

3×310×3=930

2×65×6=1230

1×103×10=1030

25,13,310


(b) 712,59,916

Sol :

LCM of 12, 9, 16 is 144

7×1212×12=84144

5×169×16=80144

9×916×9=81144

712,916,59



Q10 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 10

Arrange in ascending order

(a) 1115,34,1320

Sol :

LCM of 15, 4, 20 is 60

11×415×4=4460

3×154×15=4560

13×320×3=3960

3960<4460<4560

1320<1115<34


(b) 512,718,1127

Sol :

LCM of 12, 8, 27 is 108

5×912×9=45108

7×618×6=42108

11×427×4=44108

718,1127,512



Q11 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 11

Simplify the following, expressing your answer in the simplest form

(a) 1724+124

Sol :
=1724+124=17+124=1824=34

(b) 1415+1115+1115

Sol :

1415+1115+1115

=1415+1115+1615

=14+11+1615

=4115=21115


(c) 5616

Sol :

=5616

=516

=46=23


(d) 1267917

Sol :

=1267917=907647=90647=267=357


(e) 181219+231819151419

Sol :

181219+231819151419

=(18+2315)+1219+18191419=26+12+181419=26+1619=494+1619=51019=261619



Q12 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 12

(a) 151+414

Sol :

=15+414=15+174=60+174=774=1914


(b) 271315

Sol :

=27315=27165=135165=1195=2345


(c) 61278

Sol :

=61278=61238=488238=4658=5818



Q13 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 13

(a) 125+314+710

=75+134+710=28+65+1420=10720=5720


(b) 7615+41112+3730

=11115+5912+2730

=444+295+19460

=93360=151120



Q14 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 14

(a) 523516+256

=173316+176

=3431+176

=206

=313



(b) 35241736+1116

=77244336+1116

=462172+99144

=389144

=2101144



Q15 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 15

(a) 615(4310112)

=315(431032)

=315431510

=3152810

=622810=3410

=325


(b) 359(2131512)+156

=329(731712)+116

=329281712+116

=3291112+116

=12833+6636

=16136

=41736



Q16 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 16

If in a mushroom 1920 is water, what fraction of it is solid matter?

Sol :

The fraction of mushroom in solid matter

=11920=201920=120



Q17 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 17

During a campaign an army loses 110 of its member in battle and 15 by sickness what fraction survive?

Sol :

The fraction of campaign survives 
=1(110+15)=1310=10310=710



Q18 | Ex-2A | Class 7 | Schand New Learning Composite | Fractions and Decimals | Chapter 2| myhelper

Question 18

In a certain magazine 1127 consists of advertisements and 13 of illustrations, what fraction is readable matter

Sol :

The fraction in readable matter

=1(1127+13)=111+927=12027=272027=727

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