S.chand mathematics solution class 8 chapter 11 time and work

 EXERCISE 11


Q1 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper


Question 1

A can do 34 of the work in 12 days . In how many days can he complete 18th of the work ?

Sol :

⇒A can do 34 of work in 12 days

⇒ A can do 1 work in 12×43 days And  [Multiplying both side by 4/3]

⇒ A can do 18 work in 12×43×18 days [Multiplying both side by 1/8]

=4×12 days

= 2 days

 


Q2 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 2

Tanu can do a piece of work in 24 days and Manisha can do it in 30 days . How long will they take to do the work working together ?

Sol :

⇒Tanu can do a piece of work in 24 days

⇒So Tanu's one day work =124

⇒Manisha can do the same work in 30 days

⇒So Manisha's one day work =130

⇒We know that

⇒Tanu and Manisha's one day work = Tanu's one day work + Manisha's one day work

=124+130 [Taking LCM]

=5+4120

=9120

=340

⇒Tanu and Manisha's one day work =340

⇒Total time required for completing work 1one day work=1340

⇒So Tanu and Manisha can complete the same work in =403=1313 days.

 


Q3 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 3

A and B can polish the floors of a building in 18 days . A alone can do 16 of this job in 4 days . in how many days can B alone polish the floors ?

Sol :

⇒A alone complete whole work in =416=4×61 = 24 days

⇒A's one day work =124

⇒(A and B)'s one day work =118

⇒Also , (A+B)'s one day work = A's one day work + B's one day work

118=124+1x

4372=1x

172=1x

⇒x = 72

72 days

 


Q4 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 4

A and B can weave a certain number of baskets in 12 days and 15 days respectively . They work together for 5 days and then B leaves . In how many days will A finish the rest of the work ?

Sol :

⇒A's one day work =112

⇒B's one day work =115

⇒(A + B)'s one day work = A's one day work + B's one day work

=112+115

=5+460

=960

=320

⇒(A + B)'s one day work =320

⇒They work together for 5 days =5×320=34

⇒Remaining work =134

=434=14

⇒A can complete all work in 12 days . So , remaining work can be done in =14×12 days

= 3 days

 


Q5 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 5

A , B and C working together take 8 min . to address a pile of envelopes . A and B together would take 10 min ; A and C together would take 15 min . How long would each take working alone ?

Sol :

⇒(A + B + C)'s one unit work =18

⇒(A + B)'s one unit work =110

⇒(A + C)'s one unit work =115

⇒C's one unit work = (A + B + C)'s one unit work  - (A + B)'s one unit work

=18110

=5440=140

∴C alone take 40 min

⇒B's one unit work = (A + B + C)'s one unit work  - (A + C)'s one unit work

=18115

=158120=7120

∴B alone take 1207 min

⇒A's one unit work = (A + B + C)'s one unit work  - B's one unit work - C's one unit work

=187120140

=1573120=5120=124

∴A alone take 24 min

A→24 min ; B→1207 min ; C→40 min

 


Q6 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 6

A and B can do a piece of work in 6 days and 4 days respectively . A started the work ; worked at it for 2 days and then was joined by B . Find the total time taken to complete the work .

Sol :

⇒A's one day work =16

⇒B's one day work =14

⇒A's 2 days work =2×16=13

⇒Remaining work =113

=313=23..(i)

⇒(A+B)'s one day work = A's one day work + B's one day work

=16+14

=2+312=512

or

⇒Total time required to complete work together=1one day work =1512=125

⇒Time to complete the remaining work together =23×125 =85..(ii)

⇒Total time required to complete work = A's alone working time + (A+B)'s working together time

=2+85

=10+85

=185=335

 


Q7 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 7

780 is paid for a task which A can do in 6 days , B in 8 days and C in 4 days . If all work together , how much money should each receive ?

Sol :

⇒A's one day work =16

⇒B's one day work =18

⇒C's one day work =14

∴Ratio of shares of money of A , B and C = Ratio of their one day work

=16:18:14 =16×24:18×24:14×24 [L.C.M of 6 , 8 and 24]

= 4 : 3 : 6

∴Sum of the ratios = 4 + 3 + 6 = 13

⇒A's share =413×780 = 240

⇒B's share =313×780 = 180

⇒C's share =613×780 = 360

A→240 , B→180 , C→360

 ALTERNATE METHOD

⇒A's one day work =16

⇒B's one day work =18

⇒C's one day work =14

Total work done=16+18+14

=4+3+624=1324

∴Shares of money of A , B and C = Ratio of their one day work / Total work × Total money

⇒A's share 161324×780

=413×780 = 240

⇒B's share 181324×780

=313×780 = 180

⇒C's share 141324×780

=613×780 = 360

A→240 , B→180 , C→360



Q8 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 8

X works thrice as fast as Y . If Y alone can complete a job in 18 days , find how ,many days will X and Y together take to complete the job .

Sol :

⇒Y's one day work =118

A.T.Q

⇒3X=Y

X=Y3

X=183

⇒X=6

⇒X's one day work =16

⇒(X+Y)'s one day work = X's one day work + Y's one day work

=16+118

=3+118=418=29

⇒Total time required by (X+Y) to complete work =1one day work =129 =92 or =412 days

 


Q9 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 9

A can do a job in 20 days , B in 30 days and C in 60 days . If A is helped by B and C on every third day , then in how many days will the job be finished ?

Sol :

⇒A's one day work =120..(i)

⇒(A+B+C)'s one day work = A's one day work + B's one day work + C's one day work

=120+130+160

=3+2+160

=660=110..(i)

⇒According to question, A work starting two days alone and on every third day all together work .

Total time to complete work = 1st day + 2nd day + 3rd day

1 and 2 day equal to (i) and 3 day equal to (ii)

=120+120+110

=1+1+220=420=15

Which means in 3 days 1/5 work is completed

3 days=15 work

3×5=1 work

= 15 days to complete whole work

 


Q10 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 10

Sonia can copy 50 pages in 10 hours . Priya and Sonia can copy 300 pages in 40 hours . In how much time can Priya copy 30 pages ?

Sol :

⇒Sonia in 10 hours can copy 50 pages

∴In 1 hour sonia can copy 5010=51 pages

⇒Priya and Sonia together in 40 hours can copy 300 pages

∴Priya and Sonia together in 1 hours can copy 30040=304 pages

⇒Priya's 1 hour work = Priya and Sonia together in 1 hours work - Sonia's 1 hour work

=30451

=30204=104=52

⇒Number of hours required to complete the work =Work to be doneone day work

=3052

=5×25

= 12 hours

 


Q11 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 11

A tap can fill a cistern in 15 minutes and another can empty it in 18 minutes . Find in how many minutes the tank will be filled up ?

Sol :

⇒Tank filled by tap in one hour =115 part

⇒Tank empty by tap in one hour =118 part

⇒Tank filled in one hour when both taps are open =115118

=6590=190

= 90 mins the tank will be filled up

 


Q12 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 12

Two taps can fill a cistern in 15 hours and 20 hours respectively . A third tap can empty it in 30 hours . How long will they take to fill the cistern if all the taps are opened ?

Sol :

⇒Tank filled by first tap in one hour =115 part

⇒Tank filled by second tap in one hour =120 part

⇒Tank empty by third tap in one hour =130 part

⇒Tank filled in one hour when all three taps are open =115+120130

=4+3260=560=112

= 12 hours take the tank to fill up

 


Q13 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 13

Two taps running together can fill a bath in 4 minutes , which is filled by one of the taps by itself in 7 minutes . How long would it take if the other pipe is running by itself ?

Sol :

⇒Bathtub filled by (1st + 2nd) taps in one hour =14 part

⇒Bathtub filled by first tap in one hour =17 part

⇒Bathtub filled by (1st + 2nd) taps in one hour = time taken by 1st tap in one hour + time taken by 2nd tap in one hour

14=17+x

1417=x

7428=x

x=328

Time taken by Second tap =283=913 minutes

 


Q14 | Ex-11 | Cl-8 | Schand Composite Mathematics | Time and Work | Myhelper

Question 14

A cistern can be filled by 3 taps A, B and C when turned on separately in 12 min , 10 min and 15 min respectively . If all are turned on together for 223 minutes and if B and C are then turned off , how much time will A alone take to fill the cistern ?

Sol :

⇒Time taken when all 3 taps are open for a unit time = Tap A open for unit time + Tap B open for unit time + Tap C open for unit time

=112+110+115

=5+6+460=1560=14

A.T.Q

⇒All are turned for 223 minutes =14×223 =14×83=23

⇒Remaining cistern to be filled =123 =323=13

⇒Tap A alone fill the remaining cistern [1/3 of 12min] =13×12

= 4 minutes

 


 

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