Exercise 8A
Page-124Question 1:
Express each of the following ratios in simplest form:
(i) 24 : 40
(ii) 13.5 : 15
(iii) 623:712
(iv) 16:19
(v) 4:5:92
(vi) 2.5 : 6.5 : 8
Answer 1:
(i) HCF of 24 and 40 is 8.
∴ 24 : 40 = 2440= 24 ÷ 840 ÷ 8= 35 = 3 : 5
Hence, 24 : 40 in its simplest form is 3 : 5.
(ii) HCF of 13.5 and 15 is 1.5.
13.515=135150The HCF of 135 and 150 is 15.=135 ÷ 15150 ÷ 15=910
Hence, 13.5 : 15 in its simplest form is 9 : 10.
(iii) 203 : 152=40 : 45
The HCF of 40 and 45 is 5.
∴ 40 : 45 = 4045=40 ÷ 545 ÷ 5=89 = 8 : 9
Hence, 623 : 712 in its simplest form is 8 : 9
(iv) 9 : 6
The HCF of 9 and 6 is 3.
Hence, 16:19 in its simplest form is 3 : 2.
(v) LCM of the denominators is 2.
The HCF of these 3 numbers is 1.
∴ 8 : 10 : 9 is the simplest form.
(vi) 2.5 : 6.5 : 8 = 25 : 65 : 80
The HCF of 25, 65 and 80 is 5.
∴ 25 : 65 : 80 = 256580= 25 ÷ 565 ÷ 580 ÷ 5=51316 = 5 : 13 : 16
Question 2:
Express each of the following ratios in simplest form:
(i) 75 paise : 3 rupees
(ii) 1 m 5 cm : 63 cm
(iii) 1 hour 5 minutes : 45 minutes
(iv) 8 months : 1 year
(v) (2 kg 250 g) : (3 kg)
(vi) 1 km : 750 m
Answer 2:
(i) Converting both the quantities into the same unit, we have:
75 paise : (3 × 100) paise = 75 : 300
= 75300= 75 ÷ 75300 ÷ 75=14 (∵ HCF of 75 and 300 = 75)
= 1 paise : 4 paise
(ii) Converting both the quantities into the same unit, we have:
105 cm : 63 cm = 10563=105÷2163÷21= 53 (∵ HCF of 105 and 63 = 21)
= 5 cm : 3 cm
(iii) Converting both the quantities into the same unit
65 min : 45 min = 6545= 65÷545÷5=139 (∵ HCF of 65 and 45 = 5)
= 13 min : 9 min
(iv) Converting both the quantities into the same unit, we get:
8 months : 12 months = 812=8÷412÷4=23 (∵ HCF of 8 and 12 = 4)
= 2 months : 3 months
(v) Converting both the quantities into the same unit, we get:
2250g : 3000 g = 22503000=2250÷7503000÷750= 34 (∵ HCF of 2250 and 3000 = 750)
= 3 g : 4 g
(vi) Converting both the quantities into the same unit, we get:
1000 m : 750 m = 1000750=1000÷250750÷250 = 43 (∵ HCF of 1000 and 750 = 250)
= 4 m : 3 m
Question 3:
If A : B = 7 : 5 and B : C = 9 : 14, find A : C.
Answer 3:
AB = 75 and BC = 914
Therefore, we have:
AB×BC = 75×914AC = 910
∴ A : C = 9 : 10
Question 4:
If A : B = 5 : 8 and B : C = 16 : 25, find A : C.
Answer 4:
AB=58 and BC = 1625Now, we have:AB×BC = 58×1625⇒AC = 25
∴ A : C = 2 : 5
Question 5:
If A : B = 3 : 5 and B : C = 10 : 13, find A : B : C.
Answer 5:
A : B = 3 : 5
B : C = 10 : 13 = 10÷213÷2=5 :132
Now, A : B : C = 3 : 5 : 132
∴ A : B : C = 6 : 10 : 13
Question 6:
If A : B = 5 : 6 and B : C = 4 : 7, find A : B : C.
Answer 6:
We have the following:
A : B = 5 : 6
B : C = 4 : 7 = 47 = 4×647×64= 6 : 212
∴ A : B : C = 5 : 6 : 212 = 10 : 12 : 21
Question 7:
Divide Rs 360 between Kunal and Mohit in the ratio 7 : 8.
Answer 7:
Sum of the ratio terms = 7 + 8 = 15
Now, we have the following:
Kunal's share = Rs 360 ×715= 24×7 = Rs 168
Mohit's share = Rs 360 ×815 = 24×8 = Rs 192
Question 8:
Divide Rs 880 between Rajan and Kamal in the ratio 15:16.
Answer 8:
Sum of the ratio terms = 15+16=1130
Now, we have the following:
Rajan's share = Rs 880 ×151130 = Rs 880 ×611 = Rs 80×6 = Rs 480
Kamal's share = Rs 880 ×161130= Rs 880 ×511= Rs 80 ×5 = Rs 400
Question 9:
Divide Rs 5600 between A, B and C in the ratio 1 : 3 : 4.
Answer 9:
Sum of the ratio terms is (1 + 3 + 4) = 8
We have the following:
A's share = Rs 5600 ×18 =Rs 56008 = Rs 700
B's share = Rs 5600 ×38= Rs 700 × 3 = Rs 2100
C's share = Rs 5600 ×48 =Rs 700 ×4 = Rs 2800
Question 10:
What number must be added to each term to the ratio 9 : 16 to make the ratio 2 : 3?
Answer 10:
Let x be the required number.
Then, (9 + x) : (16 + x) = 2 : 3
⇒9+x16+x = 23⇒27 + 3x = 32 + 2x⇒x =5
Hence, 5 must be added to each term of the ratio 9 : 16 to make it 2 : 3.
Question 11:
What number must be subtracted from each term of ratio 17 : 33 so that the ratio becomes 7 : 15?
Answer 11:
Suppose that x is the number that must be subtracted.
Then, (17 − x) : (33 − x) = 7 : 15
⇒17 - x33 - x=715⇒255 - 15x = 231 - 7x ⇒8x = 255 - 231 = 24⇒x = 3
Hence, 3 must be subtracted from each term of ratio 17 : 33 so that it becomes 7 : 15.
Question 12:
Two numbers are in the ratio 7 : 11. If added to each of the numbers, the ratio becomes 2 : 3. Find the numbers.
Answer 12:
Suppose that the numbers are 7x and 11x.
Then, (7x + 7) : (11x + 7) = 2 : 3
⇒ 7x + 711x + 7=23
⇒ 21x + 21 = 22x + 14
⇒ x = 7
Hence, the numbers are (7 × 7 =) 49 and (11 × 7 =) 77.
Question 13:
Two numbers are in the ratio 5 : 9. On subtracting 3 from each, the ratio becomes 1 : 2. Find the numbers.
Answer 13:
Suppose that the numbers are 5x and 9x.
Then, (5x − 3) : (9x − 3) = 1 : 2
⇒ 5x - 39x -3=12
⇒ 10x − 6 = 9x − 3
⇒ x = 3
Hence, the numbers are (5 × 3 =) 15 and (9 × 3 =) 27.
Question 14:
Two numbers are in the ratio 3 : 4. If their LCM is 180, find the numbers.
Answer 14:
Let the numbers be 3x and 4x.
Their LCM is 12x.
Then, 12x = 180
⇒ x = 15
∴ The numbers are (3 × 15 =) 45 and (4 × 15 =) 60.
Question 15:
The ages of A and B are in the ratio 8 : 3. Six years hence, their ages will be in the ratio 9 : 4. Find their present ages.
Answer 15:
Suppose that the present ages of A and B are 8x yrs and 3x yrs.
Then, (8x + 6) : (3x + 6) = 9 : 4
⇒ 8x+63x+6= 94
⇒ 32x + 24 = 27x + 54
⇒ 5x = 30
⇒ x = 6
Now, present age of A = 8 × 6 yrs = 48 yrs
Present age of B = 3 × 6 yrs = 18 yrs
Question 16:
The ratio of copper and zinc in an alloy is 9 : 5. If the weight of copper in the alloy is 48.6 grams, find the weight of zinc in the alloy.
Answer 16:
Suppose that the weight of zinc is x g.
Then, 48.6 : x = 9 : 5
⇒ x = 48.6×59=2439 = 27
Hence, the weight of zinc in the alloy is 27 g.
Question 17:
The ratio of boys and girls in a school is 8 : 3. If the total number of girls be 375, find the number of boys in the school.
Answer 17:
Suppose that the number of boys is x.
Then, x : 375 = 8 : 3
⇒ x = 8×3753=8×125 = 1000
Hence, the number of girls in the school is 1000.
Question 18:
The ratio of monthly income to the savings of a family is 11 : 2. If the savings be Rs 2500, find the income and expenditure.
Answer 18:
Suppose that the monthly income of the family is Rs x.
Then, x : 2500 = 11 : 2
⇒ x = 11×25002=11×1250
⇒ x = Rs 13750
Hence, the income is Rs 13,750.
∴ Expenditure = (monthly income − savings)
=Rs (13750 − 2500)
= Rs 11250
Question 19:
A bag contains Rs 750 in the form of rupee, 50 P and 25 P coins in the ratio 5 : 8 : 4. Find the number of coins of each type.
Answer 19:
Let the numbers one rupee, fifty paise and twenty-five paise coins be 5x, 8x and 4x, respectively.
Total value of these coins = (5x ×100100+ 8x×50100 + 4x ×25100)
⇒5x + 8x2 + 4x4= 20x + 16x + 4x4=40x4=10x
However, the total value is Rs 750.
∴ 750 = 10x
⇒ x = 75
Hence, number of one rupee coins = 5 × 75 = 375
Number of fifty paise coins = 8 × 75 = 600
Number of twenty-five paise coins = 4 × 75 = 300
Question 20:
If (4x + 5) : (3x + 11) = 13 : 17, find the value of x.
Answer 20:
(4x + 5) : (3x + 11) = 13 : 17
⇒4x+ 53x + 11=1317⇒68x + 85 = 39x + 143⇒29x = 58⇒x = 2
Question 21:
If x : y = 3 : 4, find (3x + 4y) : (5x + 6y).
Answer 21:
xy = 34⇒x=3y4
Now, we have (3x + 4y) : (5x + 6y)
=3x +4y5x + 6y=3×3y4+4y5×3y4+6y= 9y+16y15y +24y = 25y39y=2539
= 25 : 39
Question 22:
If x : y = 6 : 11, find (8x − 3y) : (3x + 2y).
Answer 22:
xy = 611⇒x = 6y11
Now, we have:
8x -3y3x + 2y = 8×6y11 -3y3×6y11+2y=48y-33y18y + 22y =15y40y=38
∴ (8x − 3y) : (3x + 2y) = 3 : 8
Question 23:
Two numbers are in the ratio 5 : 7. If the sum of the numbers is 720, find the numbers.
Answer 23:
Suppose that the numbers are 5x and 7x.
The sum of the numbers is 720.
i.e., 5x + 7x = 720
⇒ 12x = 720
⇒ x = 60
Hence, the numbers are (5 × 60 =) 300 and (7 × 60 =) 420.
Question 24:
Which ratio is greater?
(i) (5 : 6) or (7 : 9)
(ii) (2 : 3) or (4 : 7)
(iii) (1 : 2) or (4 : 7)
(iv) (3 : 5) or (8 : 13)
Answer 24:
(i) The LCM of 6 and 9 is 18.
56=5×36×3=151879=7×29×2=1418Clearly, 1418<1518
∴ (7 : 9) < (5 : 6)
(ii) The LCM of 3 and 7 is 21.
23=2×73×7=1421 47=4×37×3=1221Clearly, 1221<1421
∴ (4 : 7) < (2 : 3)
(iii) The LCM of 2 and 7 is 14.
1×72×7=714 4×27×2= 814
Clearly, 714<814
∴ (1 : 2) < (4 : 7)
(iv) The LCM of 5 and 13 is 65.
35=3×135×13= 3965 813= 8×513×5= 4065Clearly, 3965<4065
∴ (3 : 5) < (8 : 13)
Question 25:
Arrange the following ratios in ascending order:
(i) (5 : 6), (8 : 9), (11 : 18)
(ii) (11 : 14), (17 : 21), (5 : 7) and (2 : 3)
Answer 25:
(i) We have 56, 89 and 1118.
2 6,9, 18 3 3, 9, 9 3 1,3, 3 1,1, 1
The LCM of 6, 9 and 18 is 18. Therefore, we have:
56= 5×36×3=151889= 8×29×2=1618 1118=1118Clearly, 1118<1518<1618
Hence, (11 : 18) < (5 : 6) < (8 : 9)
(ii) We have 1114, 1721, 57 and 23.
2 14,21,7, 3 7 7,21,7, 3, 3 1,3,1, 3 1,1,1, 1
The LCM of 14, 21, 7 and 3 is 42.
1114=11×314×3=33281721=17×221×2=344257=5×67×6=304223=2×143×14=2842Clearly, 2842<3042<3328<3442Hence, (2 : 3) < (5 : 7) < (11 : 14) < (17 : 21)
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