RS Aggarwal 2019,2020 solution class 7 chapter 1 Integers Exercise 1C

Exercise 1C

Page-12

Question 1:

Divide:

(i) 65 by −13
(ii) −84 by 12
(iii) −76 by 19
(iv) −132 by 12
(v) −150 by 25
(vi) −72 by −18
(vii) −105 by −21
(viii) −36 by −1
(ix) 0 by −31
(x) −63 by 63
(xi) −23 by −23
(xii) −8 by 1

Answer 1:

(i) 65 ÷ (−13) = 65-13 = −5

(ii) (−84) ÷ 12 = -8412 =  −7

(iii) (−76) ÷ 19 = -7619 = −4

(iv) (−132) ÷ 12 = -13212 = −11

(v) (−150) ÷ 25 = -15025 = −6

(vi) (−72) ÷ (−18) = -72-18 = 4

(vii)  (−105) ÷ (−21) = -105-21  = 5

(viii) (−36) ÷ (−1) = -36-1 = 36

(ix) 0 ÷ (−31) =  0-31  = 0

(x)  (−63) ÷ 63 = -6363 = −1

(xi)  (−23) ÷ (−23) = -23-23 = 1

(xii) (−8) ÷ 1 =  -81 = −8

Question 2:

Fill in the blanks

(i) 72 ÷ (......) = −4
(ii) −36 ÷ (......) = −4
(iii) (......) ÷ (−4) = 24
(iv) (......) ÷ 25 = 0
(v) (......) ÷ (−1) = 36
(vi) (......) ÷ 1 = −37
(vii) 39 ÷ (......) = −1
(viii) 1 ÷ (......) = −1
(ix) −1 ÷ (......) = −1

Answer 2:

(i)
72 ÷ (x) = −4
 72x = -4x = 72-4 = -18 

(ii)
−36 ÷ (x) = −4
-36x = -4x = -36-4  = 9

(iii)
(x) ÷ (−4) = 24
x-4 = 24x = 24×(-4) = -96

(iv) 
(x) ÷ 25 = 0
x25 = 0x = 25×0 = 0

(v)
(x) ÷ (−1) = 36
x-1 = 36x = 36×(-1) = -36

(vi)
(x) ÷ 1 = −37
x1= -37x = -37×1 = -37

(vii)
39 ÷ (x) = −1
39x = -1x = -1×39 = -39

(viii) 
1 ÷ (x) = −1
1x= -1x = -1×1 = -1

(ix)
−1 ÷ (x) = −1
-1x = -1x = -1-1= 1

Question 3:

Write (T) for true and (F) for false for each of the following statements.

(i) 0 ÷ (−4) = 0
(ii) (−6) ÷ 0 = 0
(iii) (−5) ÷ (−1) = −5
(iv) (−8) ÷ 1 = −8
(v) (−1) ÷ (−1) = −1
(vi) (−9) ÷ (−1) = 9

Answer 3:

(i) True (T). Dividing zero by any integer gives zero.
(ii) False (F). Division by zero gives an indefinite number.

(iii) False (F). -5-1 = 5 

(iv)  True (T). -81= -8

(v)  False (F). -1-1 = 1

(vi) True (T). -9-1 = 9

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