RD Sharma solution class 8 chapter 7 Factorization Exercise 7.3

Exercise 7.3

Page-7.7

Question 1:

Factorize each of the following algebraic expressions:
6x(2xy) + 7y(2xy)

Answer 1:

6x(2x-y)+7y(2x-y)= (6x+7y)(2x-y)         [Taking (2x-y) as the common factor]

Question 2:

Factorize each of the following algebraic expressions:
2r(yx) + s(xy)

Answer 2:

2r(y-x)+s(x-y)=2r(y-x)-s(y-x)      [(x-y)=-(y-x)]=(2r-s)(y-x)              [Taking (y-x) as the common factor]

Question 3:

Factorize each of the following algebraic expressions:
7a(2x − 3) + 3b(2x − 3)

Answer 3:

7a(2x-3)+3b(2x-3)=(7a+3b)(2x-3)            [Taking (2x-3) as the common factor]

Question 4:

Factorize each of the following algebraic expressions:
9a(6a − 5b) −12a2(6a − 5b)

Answer 4:

9a(6a-5b)-12a2(6a-5b)=(9a-12a2)(6a-5b)     [Taking (6a-5b) as the common factor]=3a(3-4a)(6a-5b)       [Taking 3a as the common factor of the quadratic (9a-12a2)]

Question 5:

Factorize each of the following algebraic expressions:
5(x − 2y)2 + 3(x − 2y)

Answer 5:

5(x-2y)2+3(x-2y)=[5(x-2y)+3](x-2y)     [Taking (x-2y) as the common factor]=(5x-10y+3)(x-2y)

Question 6:

Factorize each of the following algebraic expressions:
16(2l − 3m)2 −12(3m − 2l)

Answer 6:

16(2l-3m)2-12(3m-2l)=16(2l-3m)2+12(2l-3m)            [(3m-2l)=-(2l-3m)]= [16(2l-3m)+12](2l-3m)           [Taking (2l-3m) as the common factor]=4[4(2l-3m)+3](2l-3m)              {Taking 4 as the common factor of [16(2l-3m)+12]}=4(8l-12m+3)(2l-3m)

Question 7:

Factorize each of the following algebraic expressions:
3a(x − 2y) −b(x − 2y)

Answer 7:

3a(x-2y)-b(x-2y)=(3a-b)(x-2y)           [Taking (x-2y) as the common factor]

Question 8:

Factorize each of the following algebraic expressions:
a2(x + y) +b2(x + y) +c2(x + y)

Answer 8:

a2(x+y)+b2(x+y)+c2(x+y)=(a2+b2+c2)(x+y)                      [Taking (x+y) as the common factor]

Question 9:

Factorize each of the following algebraic expressions:
(xy)2 + (xy)

Answer 9:

(x-y)2+(x-y)=(x-y)(x-y)+(x-y)   [Taking (x-y) as the common factor]= (x-y+1)(x-y)

Question 10:

Factorize each of the following algebraic expressions:
6(a + 2b) −4(a + 2b)2

Answer 10:

6(a+2b)-4(a+2b)2=[6-4(a+2b)](a+2b)      [Taking (a+2b) as the common factor]= 2[3-2(a+2b)](a+2b)   {Taking 2 as the common factor of [6-4(a+2b)]}=2(3-2a-4b)(a+2b)

Question 11:

Factorize each of the following algebraic expressions:
a(xy) + 2b(yx) + c(xy)2

Answer 11:

a(x-y)+2b(y-x)+c(x-y)2=a(x-y)-2b(x-y)+c(x-y)2   [(y-x)=-(x-y)]= [a-2b+c(x-y)](x-y)= (a-2b+cx-cy)(x-y)

Question 12:

Factorize each of the following algebraic expressions:
−4(x − 2y)2 + 8(x −2y)

Answer 12:

-4(x-2y)2+8(x-2y)= [-4(x-2y)+8](x-2y)   [Taking (x-2y) as the common factor]= 4[-(x-2y)+2](x-2y)   {Taking 4 as the common factor of [-4(x-2y)+8]}= 4(2y-x+2)(x-2y)

Question 13:

Factorize each of the following algebraic expressions:
x3(a − 2b) + x2(a − 2b)

Answer 13:

x3(a-2b)+x2(a-2b)=(x3+x2)(a-2b)       [Taking (a-2b) as the common factor]= x2(x+1)(a-2b)      [Taking x2 as the common factor of (x3+x2)]

Question 14:

Factorize each of the following algebraic expressions:
(2x − 3y)(a + b) + (3x − 2y)(a + b)

Answer 14:

(2x-3y)(a+b)+(3x-2y)(a+b)=(2x-3y+3x-2y)(a+b)   [Taking (a+b) as the common factor]=(5x-5y)(a+b)=5(x-y)(a+b)                      [Taking 5 as the common factor of (5x-5y)]

Question 15:

Factorize each of the following algebraic expressions:
4(x + y) (3a − b) +6(x + y) (2b 3a)

Answer 15:

4(x+y)(3a-b)+6(x+y)(2b-3a) =2(x+y)[2(3a-b)+3(2b-3a)]                {Taking [2 (x+y)] as the common factor}=2(x+y)(6a-2b+6b-9a)=2(x+y)(4b-3a)

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