Exercise 18.1
Page-18.4Question 1:
Construct a quadrilateral ABCD in which AB = 4.4 cm, BC = 4 cm, CD = 6.4 cm, DA = 3.8 cm and BD = 6.6 cm.
Answer 1:
First, we draw a rough sketch of the quadrilateral ABCD and write down its dimensions along the sides.We may divide the quadrilateral into two constructible triangles ABD and BCD.Steps of Construction:Step I: Draw BD=6.6 cmStep II: With B as the centre and radius BC=4 cm, draw an arc.Step III: With D as the centre and radius 6.4 cm, draw an arc to intersect the arc drawn in Step II at C.Step IV: With B as the centre and radius 4.4 cm, draw an arc on the side BD opposite to that of C.Step V: With D as the centre and radius 3.8 cm, draw an arc to intersect the arc drawn in Step IV at A.Step VI: Join BA, DA, BC and CDThe quadrilateral ABCD so obtained is the required quadrilateral.
Question 2:
Construct a quadrilateral ABCD such that AB = BC = 5.5 cm, CD = 4 cm, DA = 6.3 cm and AC = 9.4 cm. Measure BD.
Answer 2:
Steps of construction:Step I: Draw AB=5.5 cmStep II: With B as the centre and radius BC=5.5 cm, draw an arc.Step III: With A as the centre and radius AC=9.4 cm, draw an arc to intersect the arc drawn in Step II at C.Step IV: With C as the centre and radius CD=4 cm, draw an arc.Step V: With A as the centre and radius AD=6.3 cm, draw an arc to intersect the arc drawn in Step IV at D.Step VI: Join DA, BC, AC and CD.The quadrilateral ABCD so obtained is the required quadrilateral.
Question 3:
Construct a quadrilateral XYZW in which XY = 5 cm, YZ = 6 cm, ZW = 7 cm, WX = 3 cm and XZ = 9 cm.
Answer 3:
Steps of construction:Step I: Draw XZ=9 cmStep II: With X as the centre and radius 5 cm, draw an arc above XZ.Step III: With Z as the centre and radius 6 cm, draw an arc to intersect the arc drawn in Step II at Y above XZ.Step IV: With Z as the centre and radius 7 cm, draw an arc below XZ.Step V: With X as the centre and radius 3 cm, draw an arc to intersect the arc drawn in Step IV at W below XZ.Step VI: Join XY, YZ, ZW and XW.The quadrilateral WXYZ so obtained is the required quadrilateral.
Question 4:
Construct a parallelogram PQRS such that PQ = 5.2 cm, PR = 6.8 cm and QS = 8.2 cm.
Answer 4:
In a parallelogram opposite sides are equal. Thus, we have to construct a quadrilateral PQRS in whichPQ=5.2 cm, PR=6.8 cm and QS=8.2 cm.Steps of construction:Step I: Draw QS=8.2 cmStep II: With Q as the centre and radius 5.2 cm, draw an arc.Step III: With S as the centre and radius 5.2 cm, draw an arc to intersect the arc drawn in Step II at C.Step IV: With P as the centre and radius 6.8 cm.Step V: With Q as the centre and radius 5.2 cm, draw an arc to intersect the arc drawn in Step IV at A.Step VI: Join QR, QP, PS and SR.The quadrilateral PQRS so obtained is the required quadrilateral.
Question 5:
Construct a rhombus with side 6 cm and one diagonal 8 cm. Measure the other diagonal.
Answer 5:
Steps of construction:Step 1: Draw AC=8 cm.Step 2: With A as the centre and radius=6 cm, draw arcs on both sides.Step 3: With C as the centre and radius=6 cm, draw arcs on both sides, intersecting the previous arcs at points B and D.Step 4: Join BD =8.9cm.Thus, ABCD is the required rhombus.
Question 6:
Construct a kite ABCD in which AB = 4 cm, BC = 4.9 cm and AC = 7.2 cm.
Answer 6:
Steps of construction:Step I: Draw AC=7.2 cm.Step II: With A as the centre and radius 4cm, draw arcs on both sides of the line segment AC.Step III : With C as the centre and radius 4.9 cm, draw arcs on both sides of AC intersecting the previous arcs of step II at B and D.Step IV: Join BA, DA, BC and CD. Thus, the quadrilateral ABCD so obtained is the required kite.
Question 7:
Construct, if possible, a quadrilateral ABCD given AB = 6 cm, BC = 3.7 cm, CD = 5.7 cm, AD = 5.5 cm and BD = 6.1 cm. Give reasons for not being able to construct it, if you cannot.
Answer 7:
Steps of construction:Step I: Draw AB=6 cm.Step II: With A as the centre and radius 5.5 cm, draw an arc.Step III : With B as the centre and radius 6.1 cm, draw an arc to intersect the arc drawn in StepII at D.Step IV: With B as the centre and radius 3.7 cm, draw an arc on the side.Step V :With D as the centre and radius 5.7 cm, draw an arc to intersect the arc drawn in StepIV at C.Step VI: Join BD, DA, BC and CD. The quadrilateral ABCD so obtained is the required quadrilateral.
Question 8:
Construct, if possible, a quadrilateral ABCD in which AB = 6 cm, BC = 7 cm, CD = 3 cm, AD = 5.5 cm and AC = 11 cm. Give reasons for not being able to construct, if you cannot. (Not possible, because in triangle ACD, AD + CD < AC).
Answer 8:
Such a quadrilateral cannot be constructed because in a triangle, the sum of the length of its two sides must be greater than the that of the third side
But here in triangle ACD,
AD + CD = 5.5 + 3 = 8.5 cm
and AC = 11 cm
i.e., AD + CD < AC, which is not possible.
So, the construction is not possible.
No comments:
Post a Comment