RD Sharma solution class 7 chapter 11 Percentage Exercise 11.4

Exercise 11.4

Page-11.7

Question 1:

Find each of the following:
(i) 7% of Rs 7150
(ii) 40% of 400 kg
(iii) 20% of 15.125 litres
(iv) 313% of 90 km
(v) 2.5% of 600 metres

Answer 1:

(i)  7% of  Rs. 7150 = (7/100) ​× 7150 = 50050/100 = Rs.  500.50
(ii) 40% of 400 kg = (40/100) ×  400 = 16000/100 = 160 kg
(iii) 20% of 15.125 litres = (20/100) ×  15.125 =  302.5/100 = 3.025 litres
(iv) 313%=103×100×90=3 km
(v) 2.5% of 600 metres = (2.5/100) × 600 = 1500/100 = 15 metres

Question 2:

Find the number whose 1212% is 64.

Answer 2:

Let the number be x.

1212% of x=64252÷100 × x=6425×x2×100=6425×=64×2×100x=64×2×10025=512

Question 3:

What is the number, 614% of which is 2?

Answer 3:

Let the number be x.
614÷100 of x=2254÷100 × x=225×x4×100=225×=2×4×100x=2×4×10025=32

Question 4:

If 6 is 50% of a number, what is that number?

Answer 4:

Let the number be x. 
   50% of x = 6
⇒ (50/100) × x = 6
⇒ x = 600/50
⇒ x = 12
So, the number is 12.

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