Exercise 6.5
Page-6.32Question 1:
Using factor theorem, factorize each of the following polynomials:
x3 + 6x2 + 11x + 6
x3 + 6x2 + 11x + 6
Answer 1:
Now, put the

Therefore,
Now,

Hence,
Question 2:
x3 + 2x2 − x − 2
Answer 2:
Now, put the x = -1, we get
Therefore,
Now, x3 + 2x2 − x − 2 can be written as,

Hence,
Question 3:
x3 − 6x2 + 3x + 10
Answer 3:
Now, putting

Therefore,
Now,

Hence,
Question 4:
x4 − 7x3 + 9x2 + 7x − 10
Answer 4:
Now, putting
Therefore,
Now,

Where
Putting

Therefore,
Now,

From equation (i) and (ii), we get
Hence
Question 5:
3x3 − x2 − 3x + 1
Answer 5:
Now, putting

Therefore,
Now,

Hence
Question 6:
x3 − 23x2 + 142x − 120
Answer 6:
Now, putting

Therefore,
Now,

Hence
Question 7:
y3 − 7y + 6
Answer 7:
Now, putting

Therefore,
Now,

Hence
Question 8:
x3 − 10x2 − 53x − 42
Answer 8:
Now, putting

Therefore,
Now,

Hence
Question 9:
y3 − 2y2 − 29y − 42
Answer 9:
Now, putting

Therefore,
Now,

Hence
Question 10:
2y3 − 5y2 − 19y + 42
Answer 10:
Now, putting

Therefore,
Now,

Hence
Question 11:
x3 + 13x2 + 32x + 20
Answer 11:
Now, putting

Therefore,
Now,

Hence
Question 12:
x3 − 3x2 − 9x − 5
Answer 12:
Now, putting

Therefore,
Now,

Hence
Question 13:
2y3 + y2 − 2y − 1
Answer 13:
Now, putting

Now,

Hence
Question 14:
x3 − 2x2 − x + 2
Answer 14:
Now, putting

Therefore,
Now,

Hence
Question 15:
(i) x3 + 13x2 + 31x − 45 given that x + 9 is a factor
(ii) 4x3 + 20x2 + 33x + 18 given that 2x + 3 is a factor.
Answer 15:
Now,

Hence
(ii) Let
Therefore
Now,

Hence
Question 16:
x4 − 2x3 − 7x2 + 8x + 12
Answer 16:
Now, putting

Therefore,
Now,

Where
Putting

Therefore,
Now,

From equation (i) and (ii), we get
Hence
Question 17:
x4 + 10x3 + 35x2 + 50x + 24
Answer 17:
Now, putting

Therefore,
Now,

Where
Putting

Therefore,
Now,

From equation (i) and (ii), we get
Hence
Question 18:
2x4 − 7x3 − 13x2 + 63x − 45
Answer 18:
Now, putting

Therefore,
Now,

Where
Putting

Therefore,
Now,

From equation (i) and (ii), we get
Hence
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