Exercise 5.3
Page-5.17Question 1:
Factorize:
64a3 + 125b3 + 240a2b + 300ab2
Answer 1:
The given expression to be factorized is ![]()
This can be written in the form![]()
Take common
from the last two terms,![]()
This can be written in the following form
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Recall the formula for the cube of the sum of two numbers
![]()
Using the above formula, we have
![]()
We cannot further factorize the expression.
So, the required factorization of
is
.
Question 2:
125x3 − 27y3 − 225x2y + 135xy2
Answer 2:
The given expression to be factorized is ![]()
This can be written in the form ![]()
Take common
from the last two terms,. Then we get ![]()
![]()
This can be written in the following form![]()
![]()
Recall the formula for the cube of the difference of two numbers ![]()
Using the above formula, we have
![]()
![]()
We cannot further factorize the expression.
So, the required factorization is of
is
.
Question 3:
Answer 3:
The given expression to be factorized is
![]()
This can be written in the form
![]()
Take common
from the last two terms,. Then we get
![]()
![]()
This can be written in the following form
![]()
![]()
Recall the formula for the cube of the sum of two numbers
![]()
Using the above formula, we have
![]()
![]()
We cannot further factorize the expression.
So, the required factorization is of
is
.
Question 4:
8x3 + 27y3 + 36x2y + 54xy2
Answer 4:
The given expression to be factorized is ![]()
This can be written in the form
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Take common
from the last two terms. Then we get
![]()
This can be written in the following form
![]()
![]()
Recall the formula for the cube of the sum of two numbers
![]()
Using the above formula, we have
![]()
![]()
We cannot further factorize the expression.
So, the required factorization is of
is
.
Question 5:
a3 − 3a2b + 3ab2 − b3 + 8
Answer 5:
The given expression to be factorized is ![]()
This can be written in the form

Take common
from the third and fourth terms. Then we get
![]()
This can be written in the following form
![]()
![]()
Recall the formula for the cube of the difference of two numbers
![]()
Using the above formula, we have
![]()
![]()
This can be written in the following form
![]()
![]()
Recall the formula for the sum of two cubes
![]()
Using the above formula, we have

We cannot further factorize the expression.
So, the required factorization is of
is
.
Question 6:
x3 + 8y3 + 6x2y + 12xy2
Answer 6:
The given expression to be factorized is ![]()
This can be written in the form
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Take common
from the last two terms. Then we get
![]()
![]()
This can be written in the following form
![]()
![]()
Recall the formula for the cube of the sum of two numbers
![]()
Using the above formula, we have
![]()
![]()
We cannot further factorize the expression.
So, the required factorization is of
is
.
Question 7:
8x3 + y3 + 12x2y + 6xy2
Answer 7:
The given expression to be factorized is ![]()
This can be written in the form
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Take common 6xy from the last two terms,. Then we get
![]()
![]()
This can be written in the following form
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![]()
Recall the formula for the cube of the sum of two numbers
![]()
Using the above formula, we have
![]()
![]()
We cannot further factorize the expression.
So, the required factorization is of
is
.
Question 8:
8a3 + 27b3 + 36a2b + 54ab2
Answer 8:
The given expression to be factorized is![]()
This can be written in the form
![]()
Take common
from the last two terms,. Then we get
![]()
![]()
This can be written in the following form
![]()
![]()
Recall the formula for the cube of the sum of two numbers![]()
Using the above formula, we have ![]()
![]()
We cannot further factorize the expression.
So, the required factorization is of
is
.
Question 9:
8a3 − 27b3 − 36a2b + 54ab2
Answer 9:
The given expression to be factorized is ![]()
This can be written in the form ![]()
Take common – 18ab from the last two terms,. Then we get ![]()
![]()
This can be written in the following form![]()
![]()
Recall the formula for the cube of the difference of two numbers![]()
Using the above formula, we have ![]()
![]()
We cannot further factorize the expression.
So, the required factorization is of
is
.
Question 10:
x3 − 12x(x − 4) − 64
Answer 10:
The given expression to be factorized is ![]()
This can be written in the form

Take common – 12x from the last two terms,. Then we get![]()
![]()
This can be written in the following form![]()
![]()
Recall the formula for the cube of the difference of two numbers![]()
Using the above formula, we have![]()
![]()
We cannot further factorize the expression.
So, the required factorization is of
is
.
Question 11:
a3x3 − 3a2bx2 + 3ab2x − b3
Answer 11:
The given expression to be factorized is ![]()
This can be written in the form

Take common
from the last two terms,. Then we get ![]()
![]()
This can be written in the following form ![]()
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Recall the formula for the cube of the difference of two numbers ![]()
Using the above formula, we have ![]()
![]()
We cannot further factorize the expression.
So, the required factorization is of
is
.
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