RD Sharma 2020 solution class 9 chapter 22 Tabular Representation of Statistical Data MCQS

MCQS

Page-22.26

Question 1:

Mark the correct alternative in each of the following:
Tally marks are used to find

(a) class intervals

(b) range

(c) frequency

(d) upper limits

Answer 1:

Tally marks are used to find the frequencies.
Hence, the correct choice is (c).

Question 2:

The difference between the highest and lowest values of the observations is called

(a) frequency

(b) mean

(c) range

(d) class-intervals

Answer 2:

The difference between the highest and lowest values of the observations is called the range. Hence, the correct choice is (c).

Question 3:

The difference between the upper and the lower class limits is called

(a) mid-points

(b) class size

(c) frequency

(d) mean

Answer 3:

The difference between the upper and the lower class limits is called the class size. Hence, the correct choice is (b).

Question 4:

In the class intervals 10-20, 20-30, 20 is taken in

(a) the interval 10-20

(b) the interval 20-30

(c) both intervals 10-20, 20-30

(d) none of the intervals

Answer 4:

The given class intervals are 10-20, 20-30. In these class intervals the value 20 is lies in the class interval 20-30. Hence, the correct choice is (b).

Question 5:

In a frequency distribution, the mid-value of a class is 15 and the class intervals is 4. The lower limit of the class is

(a) 10

(b) 12

(c) 13

(d) 14

Answer 5:

Let l and m respectively be the lower and upper limits of the class. Then the mid-value of the class is and the class-size is.
Therefore, we have two equations


Subtracting the second equation from the first equation, we have

Hence, the lower limit of the class is 13. Thus, the correct choice is (c).

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Question 6:

The mid-value of a class interval is 42. If the class size is 10, then the upper and lower limits of the class are:

(a) 47 and 37

(b) 37 and 47

(c) 37.5 and 47.5

(d) 47.5 and 37.5

Answer 6:

Let l and m respectively be the lower and upper limits of the class. Then the mid-value of the class is and the class-size is.
Given that the mid-value of the class is 42 and the class-size is 10. Therefore, we have two equations


Adding the above two equations, we have

Substituting the value of m in the first equation, we have

Hence, the upper and lower limits of the class are 47 and 37 respectively. Thus, the correct choice is (a).

Question 7:

The number of times a particular item occurs in a given data is called its

(a) variation

(b) frequency

(c) cumulative frequency

(d) class-size

Answer 7:

The number of times a particular item occurs in a given data is called the frequency of the item. Hence, the correct choice is (b).

Question 8:

The width of each of nine classes in a frequency distribution is 2.5 and the lower class boundary of the lowest class 10.6. Then the upper class boundary of the highest class is

(a) 35.6

(b) 33.1

(c) 30.6

(d) 28.1

Answer 8:

The number of classes is 9 and the uniform class size is 2.5. The lower limit of the lower class (first class) is 10.6. Therefore, the upper limit of the last class is

Hence, the correct choice is (b).

Question 9:

The following marks were obtained by the students in a test:
81, 72, 90, 90, 86, 85, 92, 70, 71, 83, 89, 95, 85, 79, 62

The range of the marks is

(a) 9

(b) 17

(c) 27

(d) 33

Answer 9:

The marks obtained by the students are 81, 72, 90, 90, 86, 85, 92, 70, 71, 83, 89, 95, 85, 79 and 62.
The highest and lowest marks are 95 and 62 respectively. Therefore, the range of marks is

Hence, the correct option is (d).

Question 10:

Tallys are usually marked in a bunch of

(a) 3

(b) 4

(c) 5

(d) 6

Answer 10:

Tallies are usually marked in a bunch of 4. Hence, the correct option is (b). 

Question 11:

Let l be the lower class limit of a class-interval in a frequency distribution and m be the mid point of the class. Then, the upper class limit of the class is

(a) m+$\frac{l+m}{2}$

(b) l+$\frac{m+l}{2}$

(c) 2m − 1

(d) m − 2l

Answer 11:

Given that, the lower class limit of a class-interval is l and the mid-point of the class is m. Let u be the upper class limit of the class-interval. Therefore, we have

Thus the upper class limit of the class is. Hence, the correct choice is (c).